Question

我在ac代码中使用fscanf函数来读取包含1行由空格分隔的单词，但是例如如果第一个单词是1234，那么当我打印它时输出是234，但是其他单词在文件中读取是否正确，有什么想法吗？

FILE* file = fopen(path, "r");

char arr = getc(file);

char temp[20];  

while(fscanf(file,"%s",temp)!= EOF && i<= column)
{
 printf("word %d: %s\n",i, temp);
}

Answer 1

char arr = getc（file）;

可能上面的行导致第一个字符松散。

Answer 2

char arr = getc(file);

从文件流中读取第一个字符并迭代文件流 file

Answer 3

这是发布的代码，带有我的评论

When asking a question about a run time problem, 
post code that cleanly compiles, and demonstrates the problem

FILE* file = fopen(path, "r");
// missing check of `file` to assure the fopen() was successful

char arr = getc(file);
// this consumed the first byte of the file, (answers your question)

char temp[20];  

while(fscanf(file,"%s",temp)!= EOF && i<= column)
// missing length modifier. format should be: "%19s"
// 19 because fscanf() automatically appends a NUL byte to the input
// 19 because otherwise the input buffer could be overrun,
//    resulting in undefined behaviour and possible seg fault event
// should be checking (also) for returned value == 1 
// this will fail as soon as an `white space` is encountered
// as the following call to fscanf() will not read/consume the white space
// suggest a leading space in the format string to consume white space
{
    printf("word %d: %s\n",i, temp);
    // the variable 'i' is neither declared nor modified
    //    within the scope of the posted code
}

fscanf不会读取第一个单词的第一个字符（在c中）

3 个答案: