Question

这是我的代码：

 package com.alibdeir.database;

    import android.content.Context;
    import android.support.v7.app.AppCompatActivity;
    import android.os.Bundle;
    import android.view.Menu;
    import android.view.MenuItem;
    import android.view.View;
    import android.widget.Button;
    import android.widget.TextView;
    import android.widget.Toast;

    import com.parse.GetCallback;
    import com.parse.Parse;
    import com.parse.ParseObject;
    import com.parse.ParseQuery;
    import com.parse.SaveCallback;
    import com.parse.ParseException;

    public class MainActivity extends AppCompatActivity {
        TextView output;
        Button increase;
        int currentInt;



        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_main);
            Parse.initialize(this, "QeaC0wiXsL9MyRbLaQ***********", "kDjoZVRu4OyWOGxPtPjh**************");
            output =  (TextView) findViewById(R.id.output);
            increase = (Button) findViewById(R.id.increase);
            ParseQuery query = new ParseQuery("int");
            ParseObject o = query.get-("n6zA3CHxGx");
        }
        public void increase(View v) {

            currentInt = Integer.parseInt(output.getText().toString());
            output.setText(currentInt + 1 + "");
        }
    }

注意： ParseQuery query = new ParseQuery（“int”）; ParseObject o = query.get（“n6zA3CHxGx”）;

onhover of query.get（“n6zA3CHxGx”）;我有标题中提到的错误。我正在尝试更新解析云中的对象。对象在云中。请帮忙

Answer 1

使用try { .. } catch这样尝试处理异常的代码。

try {
Parse.initialize(this, "QeaC0wiXsL9MyRbLaQ***********", "kDjoZVRu4OyWOGxPtPjh**************");
    output =  (TextView) findViewById(R.id.output);
    increase = (Button) findViewById(R.id.increase);
    ParseQuery query = new ParseQuery("int");
    ParseObject o = query.get-("n6zA3CHxGx");
} catch (com.parse.ParseException e1) {
e1.printStackTrace();
}

根据this解析论坛讨论 ACL设置默认为public read，owner-write。您可以更改这些以允许其他用户写入。

使用以下代码： -

ParseACL postACL = new ParseACL(ParseUser.getCurrentUser());
postACL.setPublicReadAccess(true);
postACL.setPublicWriteAccess(true);

未处理的异常：com.parse.parseException android studio

1 个答案: