Question

对于给定的NSstring，我需要搜索一个ip地址并显示它。下面是示例代码，但不知道它为什么不起作用。

字符串是

..
"Stories": [
    {
        "userId": "105304831528398207103",
        "story": "some story",
        "Likes": [
                 {user_id :"user id 1", user_name: "user name"}, 
                 ..... 
             ],
        "_id": {
            "$oid": "55c055af1875b0002572cf94"
        }
    }
]
..

函数searchIPString（）

(SII_Bg

SII Bg

Disconnected  ( User Disconnected )  



N/A



SII_Bg_IP

SII Bg via Router

Connected    (00:19:36)

191.30.33.55 

N/A 

)

mydata是NSData，它正在转换为NSString。
mydata包含以上值。
在newString中替换“\ n”。

但结果值为“0元素”，即使该字符串具有有效的IP地址。请让我知道我哪里出错了。

感谢

Answer 1

尝试按照模式搜索整个字符串，您不需要替换换行符

let pattern = "\\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\b"

代码就像

let pattern = "\\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\b"
do {
    let string = "Your Text"
    let regex = try NSRegularExpression(pattern: pattern, options: [])
    let matches = regex.matchesInString(string, options: [], range: NSRange(location: 0, length: string.characters.count))
} catch {

}

Answer 2

你甚至可以简化正则表达式。做这样的事。

func searchIPString(string: String) -> [String]? {
    let regex = "\\d{1,3}[.]\\d{1,3}[.]\\d{1,3}[.]\\d{1,3}"
    do {
        let regularExpresion = try NSRegularExpression(pattern: regex, options: .CaseInsensitive)
        let matches = regularExpresion.matchesInString(string, options: .ReportCompletion, range: NSMakeRange(0, string.characters.count))

        var matchingIPs = [String]()
        let convertedString = string as NSString
        matches.forEach { textCheckingResult in
            let range = textCheckingResult.range
            let foundIP = convertedString.substringWithRange(range) as String
            matchingIPs.append(foundIP)
        }

        return matchingIPs
    } catch let error as NSError{
        print("Regular Expression Format is Wrong: \(error.localizedDescription)")
    }

    return []
}

无法使用Swift 2搜索给定字符串中的模式

2 个答案: