我在我的表user_table中添加了一个新的uuid字段,其中包含现有行。由于竞争条件,我得到了#34;重复条目"迁移时出错。然后我按照这里的步骤进行操作:
http://django.readthedocs.org/en/latest/howto/writing-migrations.html
现在我的第一次和第二次迁移都在运行,但我上次的迁移给了我同样的错误。我对链接的3次迁移如下:
from __future__ import unicode_literals
from django.db import models, migrations
import uuid
class Migration(migrations.Migration):
dependencies = [
('app', '0008_label'),
]
operations = [
migrations.AddField(
model_name='user_table',
name='UUID_loc',
field=models.UUIDField(default=uuid.uuid4, null=True),
),
migrations.AlterField(
model_name='another_table',
name='Time',
field=models.CharField(default=0, max_length=3),
),
]
from __future__ import unicode_literals
from django.db import migrations, models
import uuid
def gen_uuid(apps, schema_editor):
MyModel = apps.get_model('app', 'user_table')
for row in MyModel.objects.all():
row.uuid = uuid.uuid4()
row.save()
class Migration(migrations.Migration):
dependencies = [
('app', '0009_label'),
]
operations = [
# omit reverse_code=... if you don't want the migration to be reversible.
migrations.RunPython(gen_uuid, reverse_code=migrations.RunPython.noop),
]
from __future__ import unicode_literals
from django.db import models, migrations
import uuid
class Migration(migrations.Migration):
dependencies = [
('app', '0010_label'),
]
operations = [
migrations.AlterField(
model_name='user_table',
name='UUID_loc',
field=models.UUIDField(default=uuid.uuid4, unique=True),
),
]
该链接与我非常相关,但不幸的是我收到同样的错误。现在我被困在这里我的表有UUID_loc字段,但它还不是唯一的,即第三次迁移还没有运行。有人可以提供一些见解吗?谢谢。
答案 0 :(得分:1)
我认为您应该稍微编辑第二次迁移,以防止django使用重复的uuid值更新模型。
def gen_uuid(apps, schema_editor):
MyModel = apps.get_model('app', 'user_table')
for row in MyModel.objects.all():
while True:
row.uuid = uuid.uuid4()
if not MyModel.objects.filter(uuid=row.uuid).exists():
break
row.save()
您应该再次重新运行第二次迁移,然后您应该能够毫无问题地运行第三次迁移。