如何在同一标签中的三个不同文件夹中显示图像

Question

 $sql=mysql_query(
"SELECT ssmid, image FROM user_photos_offline WHERE ssmid='$ssmid' AND status='1'
UNION
SELECT ssmid, image FROM user_profile_pic WHERE ssmid='$ssmid' AND status='1'
UNION
SELECT ssmid, image FROM user_family_photos WHERE ssmid='$ssmid' AND status='1' " 
);
while($row=mysql_fetch_assoc($sql)){
 echo  $result = $row['image'];// Here i got all images name from DB
 }

此代码工作正常，$结果我从DB获取所有值，但这个图像我移动了三个不同的文件夹，这些是文件夹名称裁剪图像，家庭照片，个人资料照片     如何在<img src='?????'>

中显示图像文件夹名称

Answer 1

  

mysql_ *扩展在PHP 5.5.0中已弃用，并且已在PHP中删除   7.0.0。相反，应使用MySQLi或PDO_MySQL扩展名。

试试这个

$folder_names = array("cropped-images","profile-photos","family-photos");
$i = 0;
while($row=mysql_fetch_assoc($sql)){
  echo  $result = $row['image'];// Here i got all images name from DB
  echo "<img src='".$folder_names[$i]."/".$result."'>";      
  $i++;
}