Question

我有条件需要根据employment_status = active和account_type != admin过滤下拉列表

这是我的代码：

<?php
$employeesList = array();
$employees = Employee::model()->findAllByAttributes(array('employment_status' => 'active', 'account_type' ??? 'admin'));
foreach ($employees as $employee) {
   $employeesList[$employee->company_id] = $employee->getName();
} 
?>

我如何获得'account_type' != 'admin'？

请帮忙。

Answer 1

有多种方法可以做到这一点：

$employees = Employee::model()->findAllByAttributes(array('employment_status' => 'active'), 'account_type' != 'admin');

或者，

$criteria=new CDbCriteria;
$criteria->condition = "account_type != 'admin' AND employment_status = :status";
$criteria->params = array (
    ':status' => "active",
);
$employees = Employee::model()->findAll( $criteria );

Answer 2

在yii1中，以下代码对我有用。

WebDriverWait(self.your_webelemt_object, 20, ignored_exceptions=[NoSuchElementException, the_other_exceptions]).  # the rest omitted for brevity

在YII中不一样的条件

2 个答案: