我想将图像包在圆柱形杯子上。我使用html5和Java脚本来实现这个解决方案。我从这个链接中得到了一些想法:https://stackoverflow.com/questions/31424117/。 但我没有从这个链接获得解决方案。
我想将剩余的图像包裹在杯子后面,就像模制其余部分并添加一些旋转按钮一样。
<canvas id="canvas"></canvas>
<script>
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var productImg = new Image();
productImg.onload = function () {
var iw = productImg.width;
var ih = productImg.height;
console.log("height");
canvas.width = iw;
canvas.height = ih;
ctx.drawImage(productImg, 0, 0, productImg.width, productImg.height, 0, 0, iw, ih);
//start();
// outline
/*ctx.beginPath();
ctx.moveTo(88, 235.734375);
ctx.bezierCurveTo(88, 234.734375, 204, 298, 327, 234.734375);
ctx.stroke();*/
};
productImg.src = "https://d2z4fd79oscvvx.cloudfront.net/0018872_inspirational_teacher_mug.jpeg";
var img = new Image();
img.onload = start;
img.src = "http://blog.foreigners.cz/wp-content/uploads/2015/05/Make-new-friends.jpg";
var pointer = 0;
function start() {
var iw = img.width;
var ih = img.height;
//canvas.width = iw + 20;
//canvas.height = ih + 20;
var x1 = 125;
var y1 = 130;
var x2 = 180;
var y2 = 190;
var x3 = 405;
var y3 = 150;
// calc line equations slope & b (m,b)
var unitT = 1 / iw;
// draw vertical slices
for (var X = 0, t = 0; X < iw; X++, t += unitT) {
var xTop = (1 - t) * (1 - t) * x1 + 2 * (1 - t) * t * x2 + t * t * x3;
var yTop = (1 - t) * (1 - t) * y1 + 2 * (1 - t) * t * y2 + t * t * y3;
ctx.drawImage(img, X + pointer, 0, 1, ih, xTop, yTop, 0.85, ih - 600);
}
如果我更改上面代码中的指针值,则保留剩余图像 拉伸。
var pointer = 100 ;
我想将图像包裹在整个杯子上并左右旋转。
答案 0 :(得分:7)
我已经在你的傻瓜身边玩了一段时间并想出了这个: http://plnkr.co/edit/83xAr99FjswWg0GHjDvJ?p=preview
function start() {
var iw = img.width;
var ih = img.height;
var xOffset = 125,
yOffset = 122;
var a = 122.0;
var b = 30.0;
var scaleFactor = iw / (2*a); //how many times original image is greater compared to our rendering area?
// draw vertical slices
for (var X = 0; X < iw; X+=1) {
var y = b/a * Math.sqrt(a*a - (X-a)*(X-a)); // ellipsis equation
ctx.drawImage(img, X * scaleFactor, 0, 6, ih, X + xOffset, y + yOffset, 1, ih - 605 + y/2);
}
}
我使用了这个省略号方程http://www.mathopenref.com/coordgeneralellipse.html并将其转换为可以从相关X坐标获得Y坐标的形式。
你可以更多地使用我的plunkr来使图像更准确地覆盖杯子,但它仍然远离现实,因为这种方法不考虑杯子表面的不同闪电特征。
答案 1 :(得分:0)
function canvas1() {
var canvas = document.getElementById("canvas1");
var ctx = canvas.getContext("2d");
var productImg = new Image();
productImg.onload = function() {
var iw = productImg.width;
var ih = productImg.height;
console.log("height");
canvas.width = iw;
canvas.height = ih;
ctx.drawImage(productImg, 0, 0, productImg.width, productImg.height,
0, 0, iw, ih);
loadUpperIMage()
};
productImg.src = "http://res.cloudinary.com/pussyhunter/image/upload/c_scale,f_auto,h_350/left_handle_cup_i7ztfs.jpg"
function loadUpperIMage() {
var img = new Image();
img.src = "https://media1.giphy.com/media/j3uyvaaslUxNe/200_s.gif"
img.onload = function() {
var iw = img.width;
var ih = img.height;
var xOffset = 102, //left padding
yOffset = 110; //top padding
//alert(ih)
var a = 75.0; //image width
var b = 10; //round ness
var scaleFactor = iw / (4 * a);
// draw vertical slices
for (var X = 0; X < iw; X += 1) {
var y = b / a * Math.sqrt(a * a - (X - a) * (X - a)); // ellipsis equation
ctx.drawImage(img, X * scaleFactor, 0, iw / 9, ih, X + xOffset, y + yOffset, 1, 174);
}
};
}
};
function canvas2() {
var canvas = document.getElementById("canvas2");
var ctx = canvas.getContext("2d");
var productImg = new Image();
productImg.onload = function() {
var iw = productImg.width;
var ih = productImg.height;
console.log("height");
canvas.width = iw;
canvas.height = ih;
ctx.drawImage(productImg, 0, 0, productImg.width, productImg.height,
0, 0, iw, ih);
loadUpperIMage()
};
productImg.src = "http://res.cloudinary.com/pussyhunter/image/upload/h_350/canter_handle_cup_xyxhdd.jpg"
function loadUpperIMage() {
var img = new Image();
img.src = "https://media1.giphy.com/media/j3uyvaaslUxNe/200_s.gif"
img.onload = function() {
var iw = img.width;
var ih = img.height;
// alert(iw)
var xOffset = 101, //left padding
yOffset = 110; //top padding
var a = 75.0; //image width
var b = 10; //round ness
var scaleFactor = iw / (4 * a);
// draw vertical slices
for (var X = 0; X < iw; X += 1) {
var y = b / a * Math.sqrt(a * a - (X - a) * (X - a)); // ellipsis equation
ctx.drawImage(img, X * scaleFactor, 0, iw / 3, ih, X + xOffset, y + yOffset, 1, 174);
}
};
}
};
function canvas3() {
var canvas = document.getElementById("canvas3");
var ctx = canvas.getContext("2d");
var productImg = new Image();
productImg.onload = function() {
var iw = productImg.width;
var ih = productImg.height;
canvas.width = iw;
canvas.height = ih;
ctx.drawImage(productImg, 0, 0, productImg.width, productImg.height,
0, 0, iw, ih);
loadUpperIMage()
};
productImg.src = "http://res.cloudinary.com/pussyhunter/image/upload/h_350/right_handle_cup_dsdhr7.jpg"
function loadUpperIMage() {
var img = new Image();
img.src = "https://media1.giphy.com/media/j3uyvaaslUxNe/200_s.gif"
img.onload = function() {
var iw = img.width;
var ih = img.height;
//alert(iw)
var xOffset = 102, //left padding
yOffset = 110; //top padding
var a = 75.0; //image width
var b = 10; //round ness
var scaleFactor = iw / (3 * a);
// draw vertical slices
for (var X = 0; X < iw; X += 1) {
var y = b / a * Math.sqrt(a * a - (X - a) * (X - a)); // ellipsis equation
ctx.drawImage(img, X * scaleFactor, 0, iw / 1.5, ih, X + xOffset, y + yOffset, 1, 174);
}
};
}
};
setTimeout(function() {
canvas1()
}, 1000);
setTimeout(function() {
canvas2()
}, 2000);
setTimeout(function() {
canvas3()
}, 3000);
function updateItems(delta)
{
var $items = $('#group').children();
var $current = $items.filter('.current');
$current = $current.length ? $current : $items.first();
var index = $current.index() + delta;
// Range check the new index
index = (index < 0) ? 0 : ((index > $items.length) ? $items.length : index);
$current.removeClass('current');
$current = $items.eq(index).addClass('current');
// Hide/show the next/prev
$("#prev").toggle(!$current.is($items.first()));
$("#next").toggle(!$current.is($items.last()));
}
$("#next").click(function () {
updateItems(1);
});
$("#prev").click(function () {
updateItems(-1);
});
// Cause initial selection
updateItems(0);
&#13;
#group div{
display: none;
}
#group div.current{
display: block;
}
#next, #prev{
width: 100px;
height 40px;
cursor:pointer;
color:red;
position:fixed;
}
#next{
float: right;
}
#prev{
float: left;
margin-left:40px;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.1/jquery.min.js"></script>
<div id="next">next</div>
<div id="prev">prev</div>
<div id="group" >
<div>
<canvas id="canvas1"></canvas>
</div>
<div>
<canvas id="canvas2"></canvas>
</div>
<div>
<canvas id="canvas3"></canvas>
</div>
</div>
&#13;