Question

我有一张桌子，人们可以发表评论：

CREATE TABLE IF NOT EXISTS `comments` (
  `id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT,
  `user` int(11) UNSIGNED NOT NULL,
  `reference` int(11),
  `data` datetime NOT NULL,
  `ip` varchar(20),
  `answer` int(11)
  PRIMARY KEY (`id`)
)

如果此评论是另一条评论的答案answer有其ID。我有这个选择：

select id, user, data, ip, answer from comments where reference = ? and answer = 0

所以我可以通过引用ID获取所有帖子评论，如果是答案则跳过它。

问题是，如果一条评论有答案，我如何在此评论中的评论中选择此答案？例如：

comment 1
answer comment 1 (1)
answer comment 1 (2)
comment 2
comment 3
comment 4
answer comment 4 (1)
answer comment 4 (2)
comment 5
...

Answer 1

我想你可以

SELECT q.id as question_id , q.user as question_user, 
       q.data as question_data, q.ip as question_ip, 
       a.id as answer_id , q.user  as answer_user, 
       a.data  as answer_data, a.ip  as answer_ip  

FROM comments q LEFT JOIN comments a on q.id=a.answer 

WHERE q.reference = ?

然后在php中，你可以遍历结果并根据你的需要组装一个数组。

评论回答mysql

1 个答案: