我正在尝试使用 Spring Boot 启动现有 Web应用程序,而根本不更改现有应用程序并将spring-boot特定内容保留在单独的模块。我有以下maven结构:
parent
web-app
boot-app
我想从web-app
启动boot-app
。
我的启动模块
的pom.xml:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<dependencies>
<!-- Spring Boot -->
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<!-- Web Application -->
<dependency>
<groupId>my.group.id.</groupId>
<artifactId>web-app</artifactId>
<version>1.0-SNAPSHOT</version>
<classifier>classes</classifier>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<version>1.2.5.RELEASE</version>
</plugin>
</plugins>
</build>
</project>
Application.java:
@EnableAutoConfiguration
@ImportResource("classpath:WEB-INF/myApp-servlet.xml")
public class Application extends SpringBootServletInitializer{
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
我的网络模块
结构:
src/main/
java/ --> Rest Endpoints etc.
webapp/ --> web resources, only important files shown
WEB-INF/
myApp-servlet.xml
web.xml
的pom.xml:
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<artifactId>web-app</artifactId>
<packaging>war</packaging>
<name>some-name</name>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<artifactId>maven-war-plugin</artifactId>
<version>2.5</version>
<configuration>
<attachClasses>true</attachClasses>
</configuration>
</plugin>
</plugins>
</build>
</project>
的web.xml:
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>My Web App</display-name>
<!-- Servlet Configuration -->
<servlet>
<servlet-name>myApp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>myApp</servlet-name>
<url-pattern>/api/*</url-pattern>
</servlet-mapping>
</web-app>
对myApp-servlet.xml中:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<context:component-scan base-package="some.corp.name.space"/>
<mvc:annotation-driven />
</beans>
我的问题
当我运行Application.java
时,我收到以下错误:
Caused by: java.io.FileNotFoundException: class path resource [WEB-INF/myApp-servlet.xml] cannot be opened because it does not exist
at org.springframework.core.io.ClassPathResource.getInputStream(ClassPathResource.java:172)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:329)
... 24 more
从我所看到的,这是因为maven-war-plugin
只包含它创建的jar中的类,而不包括webapp
目录。
我的问题
无论有没有maven-war-plugin,有没有办法让我实现这个目标?
对我来说最重要的是将boot-app
作为一个单独的模块。