Question

我在PostGIS中创建了一个表itapp_cities，用于存储城市数据。我添加了一个location列，其数据类型为geometry，用于存储城市的longitude和latitude。当我运行以下INSERT查询时，我收到如下错误。

INSERT查询：

INSERT INTO itapp_cities(city_id, city_name, city_code, state_id, location) 
  VALUES (DEFAULT,'Ada', 'ada-ok',37,POINT(34.774531000000003, -96.678344899999999));

表格定义：

CREATE TABLE itapp_cities
(
  city_id bigserial NOT NULL,
  city_name character varying(100) NOT NULL,
  city_code character varying(5) NOT NULL DEFAULT ''::character varying,
  state_id bigint NOT NULL,
  location geometry,
  CONSTRAINT itapp_cities_pkey PRIMARY KEY (city_id),
  CONSTRAINT fk_states FOREIGN KEY (city_id)
      REFERENCES itapp_states (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE CASCADE
)

错误：

ERROR:  column "location" is of type geometry but expression is of type point
LINE 2:   VALUES (DEFAULT,'Ada', 'ada-ok',37,POINT(34.77453100000000...
                                             ^
HINT:  You will need to rewrite or cast the expression.
********** Error **********

ERROR: column "location" is of type geometry but expression is of type point
SQL state: 42804

如何在此列中存储点值？我是PostGIS的新手，请原谅我这个愚蠢的问题

Answer 1

尝试此SQL并将其与insert sql query匹配

    INSERT INTO itapp_cities(city_id, city_name, slug, state_id, location) 
  VALUES (DEFAULT,'Ada', 'ada-ok',37,st_GeomFromText('POINT(34.774531000000003 -96.678344899999999)', 312));

有关详细信息，请查看此link

Answer 2

您可以使用ST_MakePoint()功能，并将SRID (Spatial Reference System Identifier)设置为ST_SetSRID()：

SELECT ST_SetSRID(ST_MakePoint(longitude, latitude),4326)

或者无论如何输入文字值，请将字符串表示提供给ST_GeomFromText()：

SELECT ST_GeomFromText('SRID=4326;POINT(34.774531 -96.6783449)')

关于dba.SE的相关答案以及更多细节和链接：

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Answer 3

根据 postGIS 文档，您的原始插入已关闭。只需在 POINT 表达式周围添加 '。

INSERT INTO itapp_cities(city_id, city_name, city_code, state_id, location) 
  VALUES (DEFAULT,'Ada', 'ada-ok',37,'POINT(34.774531000000003, -96.678344899999999)');

http://postgis.net/workshops/postgis-intro/geometries.html

如何将POINTS（LANG，LAT）存储到PostGIS中的几何类型列？

3 个答案: