Question

确定。所以我有一个表格应该获取用户信息，包括应该存储在数组中的种族信息以允许多个选择，但它也应该是可选的，这样就没有人有义务进行任何选择

输入页面种族背景（选择所有适用的选项）：

  <input type="checkbox" name="ethnicity[]" value="Indian"> American Indian or Alaska Native<br>
  <input type="checkbox" name="ethnicity[]" value="Asian"> Asian<br>
  <input type="checkbox" name="ethnicity[]" value="African-American"> Black or African-American<br>
  <input type="checkbox" name="ethnicity[]" value="Pacific"> Native Hawaiian or other Pacific Islander<br>
  <input type="checkbox" name="ethnicity[]" value="White"> White<br>

在我的processData页面上，然后将所有内容存储到变量

中

$email = filter_input (INPUT_POST, 'email');
$passwordUser = filter_input (INPUT_POST, 'passwordUser');
$phone = filter_input (INPUT_POST, 'phone');

$sex = filter_input (INPUT_POST, 'sex');
if ($sex == NULL) {
    $sex = 'unknown';
}

$age = filter_input (INPUT_POST, 'age');
$state = filter_input (INPUT_POST, 'state');

$ethnicity = filter_input (INPUT_POST, 'ethnicity', FILTER_SANITIZE_SPECIAL_CHARS, FILTER_REQUIRE_ARRAY);
if ($ethnicity !== NULL) {

}  else {
     'No answer selected.';
}
 include 'insertData.php';

然后在insertData页面上将所有信息插入表格中。

include 'database.php';

try {
$query = "INSERT INTO accounts
            (ageGroup, emailAddress, gender, password, phoneNumber, stateAbbr)
          VALUES
            (:ageGroup, :emailAddress, :gender, :passwordUser, :phoneNumber, :stateAbbr)";

$statement = $db->prepare($query);
$statement->bindValue(':ageGroup', $age);
$statement->bindValue(':emailAddress', $email);
$statement->bindValue(':gender', $sex);
$statement->bindValue(':passwordUser', $passwordUser);
$statement->bindValue(':phoneNumber', $phone);
$statement->bindValue(':stateAbbr', $state);
$statement->execute();
$statement->closeCursor();


foreach ($ethnicity as $result) {
    $query = "INSERT INTO customerethnicity
            (emailAddress, ethnicity)
          VALUES
            (:emailAddress, :ethnicity)";

    $statement = $db->prepare($query);
    $statement->bindValue(':ethnicity', $result);
    $statement->bindValue(':emailAddress', $email);
    $statement->
    execute();
    $statement->closeCursor();
}
echo "Account created successfully!";
    } catch (PDOException $e) { //Catches and handles db errors to prevent site crash

    $title = 'Error';
    $caption = 'System message:';
    $message = $e->getMessage() . '<br><br> An error has occurred. Please check the information entered and try again.';

    include 'Database_error.php';

数据库使用两个由电子邮件链接的表格，电子邮件和种族一起在桌面上创建专门为种族设计的新行。另一个表存储其余信息。几乎所有东西都有效。我可以将性别留空并存储“未知”。在桌子上，但是我不能不让民族盒子离开，并且有一个类似的“未知”。插入表中的值代替NULL而不收到此消息：

警告：在第26行的C：\ xampp \ htdocs \ FormData \ insertData.php中为foreach（）提供的参数无效

Account created successfully!

这是第26行：foreach ($ethnicity as $result) {

帐户创建成功的测试仪消息弹出，如果我查看表格，我可以看到输入的所有其他信息显示在帐户表中，但在customerethnicity表中没有显示。如果我填写信息，或者即使我将其他值留空，只选择一个或多个种族，那么一切正常。问题是没有选择种族。我需要显示一个值，表示没有选择任何内容。

Answer 1

如果条件为未设置的情况，请为复选框添加ID并具有类似的内容：
if (document.getElementById('yourCheckBoxID').checked) { alert("checked"); } else { alert("Please check"); }

Answer 2

您可以简单地测试$ethnicity＆＃34;是否＆＃34;在尝试迭代它之前的数组。

if ( is_array($ethnicity) ) {
    $query = '
        INSERT INTO customerethnicity
            (emailAddress, ethnicity)
        VALUES
            (:emailAddress, :ethnicity)
    ';

    $statement = $db->prepare($query);
    $statement->bindParam(':ethnicity', $result);
    $statement->bindParam(':emailAddress', $email);

    foreach ($ethnicity as $result) {
        $statement->execute();
        ...

sscce：

<?php
$pdo = new PDO('mysql:host=localhost;dbname=test;charset=utf8', 'localonly', 'localonly', array(
    PDO::ATTR_EMULATE_PREPARES=>false,
    PDO::MYSQL_ATTR_DIRECT_QUERY=>false,
    PDO::ATTR_ERRMODE=>PDO::ERRMODE_EXCEPTION
));
setup($pdo); // creating temporary tables for the example

// the array is more or less what you got from your filter_input script
// doInsert will extract it, so the code in that function looks like your second script
doInsert($pdo, array(
    'age'=>'21-39',
    'email'=>'emailA',
    'sex'=>'m',
    'passwordUser'=>'1234',
    'phone'=>'5678',
    'state'=>'neverneverland',
    'ethnicity'=>['de','fr','au']
));

doInsert($pdo, array(
    'age'=>'80+',
    'email'=>'emailB',
    'sex'=>'m',
    'passwordUser'=>'abcd',
    'phone'=>'9876',
    'state'=>'midleearth',
    'ethnicity'=>null
));

// example for querying the data
// not sure if that's a really good way to do it; but ...just an example ;-)
showUser($pdo, 'emailA');
showUser($pdo, 'emailB');

function doInsert($db, $params) {
    extract($params);

    try {
        $db->beginTransaction(); // that should answer your second question, see http://docs.php.net/pdo.transactions
        $query = "
            INSERT INTO soFoo
                (ageGroup, emailAddress, gender, password, phoneNumber, stateAbbr)
            VALUES
            (:ageGroup, :emailAddress, :gender, :passwordUser, :phoneNumber, :stateAbbr)
        ";
        $statement = $db->prepare($query);
        $statement->bindValue(':ageGroup', $age);
        $statement->bindValue(':emailAddress', $email);
        $statement->bindValue(':gender', $sex);
        $statement->bindValue(':passwordUser', $passwordUser);
        $statement->bindValue(':phoneNumber', $phone);
        $statement->bindValue(':stateAbbr', $state);
        $statement->execute();
        $statement->closeCursor();

        if ( is_array($ethnicity) ) {
            $query = '
                INSERT INTO soBar
                    (emailAddress, ethnicity)
                VALUES
                    (:emailAddress, :ethnicity)
            ';

            $statement = $db->prepare($query);
            $statement->bindParam(':ethnicity', $result);
            $statement->bindParam(':emailAddress', $email);

            foreach ($ethnicity as $result) {
                $statement->execute();
            }
        }

        $db->commit();
    }
    catch(Exception $e) {
        $db->rollBack();
        throw $e;
  }
}

function showUser($db, $email) {
    $statement = $db->prepare('
        (
            SELECT
                ageGroup,gender,stateAbbr
            FROM
                soFoo
            WHERE
                emailAddress=:e1
        )
        UNION ALL
        (
            SELECT
                ethnicity,null,null
            FROM
                soBar
            WHERE
                emailAddress=:e2
        )
    ');
    $statement->bindValue(':e1', $email);
    $statement->bindValue(':e2', $email);
    $statement->execute();

    $user = $statement->fetch();
    if ( !$user ) {
        echo 'no user with email=', $email, "\r\n";
    }
    else {
        printf("%s %s %s\r\n", $user['ageGroup'], $user['gender'], $user['stateAbbr']);
        $eth = $statement->fetch();
        if ( !$eth ) {
            echo '  unknown ethnicity';
        }
        else {
            do {
                echo '  ', $eth['ageGroup'], "\r\n";
            }
            while( ($eth=$statement->fetch()) );
        }
    }       
}


function setup($pdo) {
    $pdo->exec('
        CREATE TEMPORARY TABLE soFoo (
            id int auto_increment,
            ageGroup varchar(32),
            emailAddress varchar(32),
            gender varchar(32),
            password varchar(32),
            phoneNumber varchar(32),
            stateAbbr varchar(32),
            primary key(id),
            unique key(emailAddress)
        )
    ');

    $pdo->exec('
        CREATE TEMPORARY TABLE soBar (
            id int auto_increment,
            emailAddress varchar(32),
            ethnicity varchar(32),
            primary key(id),
            unique key(emailAddress, ethnicity)
        )
    ');
}

打印

21-39 m neverneverland
  au
  de
  fr
80+ m midleearth
  unknown ethnicity

Answer 3

你可以使用

if(isset($_POST['ethnicity'])){

    foreach ($ethnicity as $result) {

    ....
    }
}

Answer 4

延迟的应用，但最终我最终使用的解决方案是：

$ethnicity = filter_input (INPUT_POST, 'ethnicity', FILTER_SANITIZE_SPECIAL_CHARS, FILTER_REQUIRE_ARRAY);
if ($ethnicity !== NULL) {


}  else {
    $ethnicity = array('unknown');
}
 include 'insertData.php';
?>

希望这可能对其他人有益。

PHP：作为表中的字符串存储的ARRAY中的NULL值

4 个答案: