Question

我的课程计算每个学生的平均分数。它输出数字平均值和字母等级。有了这两个功能，我能够很好地得到每个学生的字母等级，但是我无法弄清楚如何获得每个字母等级的总数。（请注意，我不允许在此作业中使用结构，数组或向量等:(）

#include <iostream>

string letterScore(double&);
int scoreCounter(string&);

using namespace std;

int main() {
    /* repeat for 5 students */
    for (int i = 0; i < 5; i++) {

        /* for simplicity, assume avgScore has already been calculated 
           and that function returned the average scores received for 
           each student: 90, 80, 70, 60, and 50 respectively */

        // pass the average score to figure out letter grades
        string letterscore = letterScore(avgScore);
    }

    return 0;
}

string letterScore(double& avgScore) {

    int As, Bs, Cs, Ds, Fs = 0;
    string letterscore;

    if (avgScore >= 90)
    {
        letterscore = "A";
        As = scoreCounter(letterscore);
    }
    else if (avgScore >= 80 && avgScore <= 89)
    {
        letterscore = "B";
        Bs = scoreCounter(letterscore);
    }
    else if (avgScore >= 70 && avgScore <= 79)
    {
        letterscore = "C";
        Cs = scoreCounter(letterscore);
    }
    else if (avgScore >= 60 && avgScore <= 69)
    {
        letterscore = "D";
        Ds = scoreCounter(letterscore);
    }
    else if (avgScore >= 50 && avgScore <= 59)
    {
        letterscore = "F";
        Fs = scoreCounter(letterscore);
    }

    return letterscore;
}

int scoreCounter(string& letterscore) {
    int counter = 0;

    if (letterscore == "A")
    {
        counter++;
    }
    else if (letterscore == "B")
    {
        counter++;
    }
    else if (letterscore == "C")
    {
        counter++;
    }
    else if (letterscore == "D")
    {
        counter++;
    }
    else if (letterscore == "F")
    {
        counter++;
    }

    return counter;
}

我知道问题在于第二个功能以及我如何连接这两个功能。现在，As，Bs，Cs，Ds，Fs的输出为0而不是1（假设上面提到的90,80,70,60和50的平均值）。我怎样才能回到main()每个字母等级的总数？谢谢！

Answer 1

我不确切地知道你可以做什么或不做什么考虑到您不能使用数组或结构，只需使用letterScore函数解决问题，方法是将参数作为参考传递：

string letterScore(double& avgScore, int& countA, int& countB, int& countC, [etc...]) {
    string letterscore;

    if (avgScore >= 90)
    {
        letterscore = "A";
        countA++; // here is the counter !
    }
    [etc...] // do the same for other blocks

和您的main()：

int countA = countB = [etc...] = 0;
for (int i = 0; i < 5; i++) {
        string letterscore = letterScore(avgScore, countA, countB, [etc...]);
    }

从函数发出返回值

1 个答案: