Question

这个程序的主要动机是在Android ListView中显示来自SQLite的一些数据。

protected String doInBackground(String... args) {

            SQLiteOpenHelper helper = new Dictionary(contex);
            SQLiteDatabase db = helper.getReadableDatabase();

            EditText et = (EditText) findViewById(R.id.search);
            String word = et.getText().toString();
            wordlist = new ArrayList<>();

            String query = "SELECT ID, WORD" +
                    " FROM E_DICT WHERE WORD LIKE '"+word+"%' ORDER BY WORD ASC LIMIT 100 ";
                Cursor cursor = db.rawQuery(query, null);
                if(cursor!=null){
                    if(cursor.moveToFirst()){
                        do{

                            long a = cursor.getLong(0);
                            String b = cursor.getString(1);

                            HashMap<String, String> map = new HashMap<String, String>();
                            map.put(EDICT_WORD, b);
                            map.put(EDICT_ID, ""+a);
                            Log.d("RESULT", a +" " + b); //Till this this like everything seems to be ok.
                            wordlist.add(map);
                        }
                        while(cursor.moveToNext());

                    }}
            return null;
        }

现在我将数据加载到某些AsyncTask<String, String, String>中，如下所示：

        protected void onPostExecute(String file_url) {
            pDialog.dismiss();
            runOnUiThread(new Runnable() {
                public void run() {
                    ListAdapter adapter = new SimpleAdapter(
                            Main.this, wordlist, R.layout.word_list,
                            new String[] {EDICT_WORD, EDICT_ID},
                            new int[] {R.id.eDict_Word, R.id.eDict_Id});
                    setListAdapter(adapter);
                }
            });
        }

这只给了我作为listview输出的最后一个EDICT_ID。我在哪里做错了？

Answer 1

您似乎总是在创建新的HashMap，并且只返回一个值。

所以，从

移动你的HashMap

if(cursor!=null){
    if(cursor.moveToFirst()){
    ....
    HashMap<String, String> map = new HashMap<String, String>();
    while(cursor.moveToNext());
}}

到循环之外。

HashMap<String, String> map = new HashMap<String, String>();
if(cursor!=null){
    ....
}

HashMap只给我最后一个数据

1 个答案: