Question

我有当前时间和这一次。我想找出下一次与当前时间最接近的时间。

let date = NSDate()
let calendar = NSCalendar.currentCalendar()
let components = calendar.components([.Hour, .Minute], fromDate: date)
let hour = components.hour
let minutes = components.minute
let currentTime = "\(hour)" + ":" + "\(minutes)"  //output 15:24

let timesArray = ["5:45", "6:35", "7:00", "7:30", "7:50", "8:20", "8:40", "9:15", "10:10", "11:10", "12:40", "14:15", "14:50", "15:40", "16:10", "17:10", "17:40", "18:40", "19:25", "20:50"]

Answer 1

let date = NSDate()
let timesArray = ["5:45", "6:35", "7:00", "7:30", "7:50", "8:20", "8:40", "9:15", "10:10", "11:10", "12:40", "14:15", "14:50", "15:40", "16:10", "17:10", "17:40", "18:40", "19:25", "20:50"]

// create a method to convert your time to minutes
func stringToMinutes(input:String) -> Int {
    let components = input.componentsSeparatedByString(":")
    let hour = Int((components.first ?? "0")) ?? 0
    let minute = Int((components.last ?? "0")) ?? 0
    return hour*60 + minute
}

//create an array with the minutes from the original array
let timesMinutesArray:[Int] = timesArray.map { stringToMinutes($0) }

let dayMinute = stringToMinutes("15:24")
// filter out the times that has already passed
let filteredTimesArray = timesMinutesArray.filter{$0 > dayMinute }

// get the first time in your array
if let firstTime = filteredTimesArray.first {
    // find its position and extract it from the original array
    let item = timesArray[timesMinutesArray.indexOf(firstTime)!]   //  "15:40"
}

如果需要，您还可以创建扩展程序，以便在代码中的任何位置使用它，如下所示：

extension String {
    var hourMinuteValue: (hour:Int,minute:Int) {
        guard
            let hour   = Int(componentsSeparatedByString(":").first ?? ""),
            let minute = Int(componentsSeparatedByString(":").last  ?? "")
            where componentsSeparatedByString(":").count == 2
            else { return (0,0) }
        return (hour,minute)
    }
    var dayMinute:Int {
        return hourMinuteValue.hour*60 + hourMinuteValue.minute
    }
}

let time = "15:24"

let times = ["5:45", "6:35", "7:00", "7:30", "7:50", "8:20", "8:40", "9:15", "10:10", "11:10", "12:40", "14:15", "14:50", "15:40", "16:10", "17:10", "17:40", "18:40", "19:25", "20:50"]

let minutes = times.map{ $0.dayMinute }

let filteredMinutes = minutes.filter{ $0 > time.dayMinute }

if let firstTime = filteredMinutes.first {
    let item = times[minutes.indexOf(firstTime)!]   //  "15:40"
}

Swift数组。试图根据当前时间在阵列中找到下一次

1 个答案: