如何在另一个中使用一个动态Web项目?

时间:2015-10-18 21:00:37

标签: javascript java angularjs jsp

如何在我的另一个动态Web项目的控制器中调用此项目,我在指定URL

时遇到问题

这是我想要使用的项目的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>JAXRS-HelloWorld</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
  
  <servlet>
		<servlet-name>jersey-helloworld-serlvet</servlet-name>
		<servlet-class>
                     com.sun.jersey.spi.container.servlet.ServletContainer
                </servlet-class>
		<init-param>
		     <param-name>com.sun.jersey.config.property.packages</param-name>
		     <param-value>com.javacodegeeks.enterprise.rest.jersey</param-value>
		</init-param>
		<load-on-startup>1</load-on-startup>
	</servlet>

	<servlet-mapping>
		<servlet-name>jersey-helloworld-serlvet</servlet-name>
		<url-pattern>/*</url-pattern>
	</servlet-mapping>
</web-app>

这是我想在控制器中使用的项目类

package com.javacodegeeks.enterprise.rest.jersey;

import javax.ws.rs.DefaultValue;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.Response;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;

@Path("/helloWorldREST")
public class HelloWorldREST {

	@GET
	@Path("/{parameter}")
	public Response responseMsg( @PathParam("parameter") String parameter,
			@DefaultValue("Nothing to say") @QueryParam("value") String value) {

		String output = "Hello from: " + parameter + " : " + value;
        
		return Response.status(200).entity(output).build();
	}
}

这是我想要使用项目网址的控制器

angular.module('videoManagement')
.factory('videoService' ,
['$http',function($http){
    var factory={};

    factory.ali=function(){
        return $http({
            method:'GET',
            url:'/Project_name/HelloWorldREST/responseMsg',
            header:{'Content-Type': 'application/json'},
            params:{
                value:"aliasadsaeekhan"
            }
        });

    }

    return factory;

}]);

 我是angularjs的新手,请帮助我...

0 个答案:

没有答案