Question

我需要执行一个API，它的响应是XML。但XML值在XML标记内。

例如

<example>
 <item productid = "1" productname = "xxx" cost = "5.3"/>
 <item productid = "2" productname = "yyy" cost = "4.0"/>
 <item productid = "3" productname = "zzz" cost = "1.75"/>
</example>

任何人都可以告诉我我怎样才能在标签之间移动并获得元素值例如：

example:
 item:
   productid -> 1,
   productname -> xxx,
   cost -> 5.3  
 item:
   productid -> 2,
   productname -> yyy,
   cost -> 4.0 
 item:
   productid -> 3,
   productname -> zzz,
   cost -> 1.75

感谢名单

Answer 1

的XPath： http://php.net/manual/en/simplexmlelement.xpath.php

不是强制性的，你可以让所有的孩子循环使用它们，但XPath在现实世界的场景中更通用（你有多个级别的XML节点）并且更具可读性。

<?php
$xmlStr = <<<END
<example>
 <item productid = "1" productname = "xxx" cost = "5.3"/>
 <item productid = "2" productname = "yyy" cost = "4.0"/>
 <item productid = "3" productname = "zzz" cost = "1.75"/>
</example>
END;
$xml = new SimpleXMLElement($xmlStr); 

$items = $xml->xpath("//example/item");

$out = array();
foreach($items as $x) {
    $out [] = $x->attributes();
}

Answer 2

或者您可以使用DOMElement

$doc = new DOMDocument();
$doc->load('domexample.xml');
$elements = $doc->getElementsByTagName('item');

$x = 0;
foreach($elements as $element)
{
    $results[$x]['productid'] = $element->getAttribute('productid');
    $results[$x]['productname'] = $element->getAttribute('productname');
    $results[$x]['cost'] = $element->getAttribute('cost');
    $x++;
}

Answer 3

<?php

$file = "filename.xml"; 
$example = simplexml_load_file($file) or die("Error: Can't Open File");

$prodidz = array();
$prodnamez = array();
$costz = array();

foreach ($example->children() as $item)
{
 $prodidz[] = $item->attributes()->productid;
 $prodnamez[] = $item->attributes()->productname;
 $costz[] = $item->attributes()->cost;
}

?>

php获取xml内部标记内容

3 个答案: