Question

如何在单击上一个活动中的按钮时更改新活动中的微调器我在activity1中有2个按钮如果我点击第一个按钮，它应该用spinner s1打开activity2 如果单击秒，则旋转器应为s2

这是代码，我只能打开新活动

switch (v.getId()) {

        case R.id.release:
            Intent wg = new Intent("com.pttest.com.pockettankstips.release");
            startActivity(wg);
            break;
        case R.id.alpha:
            Intent cg = new Intent("com.pttest.com.pockettankstips.release");
            startActivity(cg);
            break;
        default:
            break;
    }}

Answer 1

编写FirstActivity onCreate

    Button button1 = (Button) findViewById(R.id.button1);
    Button button2 = (Button) findViewById(R.id.button2);

    button1.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View arg0) {
            Intent intent = new Intent("com.pttest.com.pockettankstips.release");
            Bundle b = new Bundle();
            b.putInt("index",1);  
            intent.putExtras(b); 
            startActivity(intent);
        }
    });


    button2.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View arg0) {
            Intent intent = new Intent("com.pttest.com.pockettankstips.release");
            Bundle b = new Bundle();
            b.putInt("index",2);  
            intent.putExtras(b); 
            startActivity(intent);          
        }
    });

编写SecondActivity（com.pttest.com.pockettankstips.release）onCreate

    Bundle b = getIntent().getExtras();
    int index = b.getInt("index");

    if(index == 1){
        //s1 spinner
        //example: show spinner1
        //spinner1.setVisibility(View.VISIBLE);
        //spinner2.setVisibility(View.GONE);        
    }else{
        //s2 spinner
        //example: show spinner2
        //spinner1.setVisibility(View.GONE);
        //spinner2.setVisibility(View.VISIBLE);
    }

打开新活动并更改微调器？

1 个答案: