我正试图在for循环中通过动画绘制一些数据。我希望它等到动画结束然后继续进行for循环。暂停似乎有效,但有时电影很长,我想关闭并转移到下一个。谁知道我怎么能做到这一点?
import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation
import time
for j in range(0,2):
fig = plt.figure(j)
mngr = plt.get_current_fig_manager()
mngr.window.setGeometry(j*256,0,256, 256)
ax = plt.axes(xlim=(0, 2), ylim=(-2, 2))
line, = ax.plot([], [], lw=2)
# initialization function: plot the background of each frame
def init():
line.set_data([], [])
return line,
# animation function. This is called sequentially
def animate(i):
x = np.linspace(0, 2, 1000)
y = np.sin(2 * np.pi * (x - 0.01 * i+j/4.))
line.set_data(x, y)
return line,
# call the animator. blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, init_func=init,
frames=200, interval=20, blit=True,repeat=False)
plt.pause(0.02*200)
plt.show(block=True)
答案 0 :(得分:0)
一种方法是使用KeyboardInterrupt
例外移动到下一个图。
为了更好的可读性,请将绘图移动到函数中:
import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation
import time
def animate_multi(j):
fig = plt.figure(j)
mngr = plt.get_current_fig_manager()
mngr.window.setGeometry(j*256,0,256, 256)
ax = plt.axes(xlim=(0, 2), ylim=(-2, 2))
line, = ax.plot([], [], lw=2)
# initialization function: plot the background of each frame
def init():
line.set_data([], [])
return line,
# animation function. This is called sequentially
def animate(i):
x = np.linspace(0, 2, 1000)
y = np.sin(2 * np.pi * (x - 0.01 * i+j/4.))
line.set_data(x, y)
return line,
# call the animator. blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, init_func=init,
frames=200, interval=20, blit=True,repeat=False)
plt.pause(0.02*200)
plt.close()
plt.show(block=True)
现在,在你的循环中除了KeyboardInterrup
并继续下一个动画:
for j in range(5):
try:
print('Working on plot', j)
animate_multi(j)
except KeyboardInterrupt:
plt.close()
注意:您可能需要按两次<Ctrl>-<C>
才能跳到下一个动画。