我的python计算器给出了无效的语法错误

Question

我无法让我的计算器工作。当我运行它时，它说y elif语句是invallid，函数在这个clode块之上，它应该可以工作。

choice = raw_input("chose an operator [1,2,3,4]")
num1 = raw_input("input number 1")
num2 = raw_input("input number 2")

if choice == 1:
    print(num1,"+",num2,"=",add(num1,num2)

elif choice == 2:
    print(num1,"-",num2,"=",minus(num1,num2)

elif choice == 3:
    print(num1,"x",num2,"=",times(num1,num2)

elif choice == 4:
    print(num1,"/",num2,"=",divide(num1,num2)
else:
    print("that's not a valid operator")

这是我的错误

  File "calculator.py", line 27
    elif choice == 2:

Answer 1

您在所有打印报表中都缺少关闭)，除了最后一个。

Answer 2

你在每一行都缺少a）

if choice == 1:
    print(num1,"+",num2,"=",add(num1,num2)   # <--- needs ) to close

注意： raw_input“询问”字符串值，在您的情况下，您应该更改

if choice == 1:    

到

if choice == "1":

否则只需使用输入

例如：

choice = input("chose an operator [1,2,3,4]:\n")  # <- added \n, puts a new line at that point