Question

我想将一个整数解析为url，所以我构建了这样的url（有3个url因为没有参数，地点或地方和整数）

urlpatterns = [
    url(r'^map/$', geov.map_view, name = "map_view"),
    url(r'^map/(?P<search_place>[^\.]+)/$', geov.map_view, name = "map_view_accurate"),
    url(r'^map/(?P<search_place>[^\.]+)/(?P<digit>\d+)/$', geov.map_view),
]

所以在我看来，我有：

def map_view(request, search_place = None, digit = 0):
    results = {}
    print(digit)
    if search_place is not None:
        query = Place_search.objects.filter(name_lower__icontains=search_place.lower()).order_by("-importance")
        results["query"] = query
    else:
        points = Place.objects.all()
        lon = points.count()

        results["points"]=points
        results["lon"] = lon

    return render_to_response("index.html", results)

但是数字总是0而查询变量没有元素。如果我只使用第二个URL（例如：“localhost：8000 / map / madrid”它可以正常工作）

Answer 1

你的第二个url regexp捕获你想要通过第三个网址捕获的内容，即搜索带有斜线和数字的地方，你应该将它改为：

urlpatterns = [
    url(r'^map/$', geov.map_view, name = "map_view"),
    url(r'^map/(?P<search_place>[\w-]+)/$', geov.map_view, name = "map_view_accurate"),
    url(r'^map/(?P<search_place>[\w-]+)/(?P<digit>\d+)/$', geov.map_view),
]

Django URL Regex没有捕获Int

1 个答案: