Question

我有一个包含这些属性和方法的java对象：

public class Student {
    private String name; 
    private String surname;
    private int age;
    private int[] qualifications = new int[4];
}

public Student(String name, String surname, int age, int[] qualifications){
    this.name = name;
    this.surname = surname;
    this.age = age;
    this.qualifications = qualifications;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public int[] getQualifications () {
    return qualifications;
}

public void setQualifications(int[] qualifications) {
    this. qualifications = qualifications;
}

我使用：

初始化对象的实例

Student a1 = new Student("John","Doe",32,new int[]{10,8,9,9});

我尝试获取并设置名称和资格。使用name属性，但它不适用于资格数组。

// it works
a1.setName("Tom");
System.out.println("Name of the student: "+a1.getName());


//it doesn't work
System.out.println("Qualifications of the student: "+a1.getQualifications());

//return:
[I@15db9742

谢谢！

Answer 1

如果“不起作用”，则表示您获得的输出如下：

学生资格：[I @ 368102c8

然后“修复”是使用Arrays.toString来打印数组：

System.out.println("Qualifications of the student: " + Arrays.toString(a1.getQualifications());

这将输出：

学生资格：[10,8,9,9]

如果你想摆脱封闭的[...]，然后使用String.substring，例如：

String arrstr = Arrays.toString(a1.getQualifications());
System.out.println("Qualifications of the student: " + arrstr.substring(1, arrstr.length() - 1));

这将输出：

学生资格：10,8,9,9

Answer 2

要打印您使用Arrays.toString(array)的数组元素，a1.getQualifications()将返回toString方法的默认实现

使用Java中的数组访问实例变量

2 个答案: