Question

我有我添加了监听器的textInputLayout。我正在尝试检查输入的电子邮件是否有效。为此，我写了下面的代码。但它不起作用。即使我给出正确的电子邮件ID，它也会显示有效的电子邮件ID。

package com.hari.ga.activities;

import android.content.Intent;
import android.os.Bundle;
import android.support.design.widget.Snackbar;
import android.support.design.widget.TextInputLayout;
import android.support.v7.app.AppCompatActivity;
import android.text.Editable;
import android.text.TextUtils;
import android.text.TextWatcher;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

import com.hari.ga.lending.R;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * Created by Shiva on 17-10-2015.
 */
public class Personal extends AppCompatActivity {

    protected Button next;
    EditText editText;
    String e;
    Boolean check;
    protected TextInputLayout emailText;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.personal_details);
        editText = (EditText)findViewById(R.id.email);
        next = (Button)findViewById(R.id.next_button);
       emailText = (TextInputLayout)findViewById(R.id.emailText);
       e = editText.getText().toString();


        emailText.getEditText().addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
                boolean c = checkEmail(e);
                if (!c) {
                    emailText.setError("valid email id is required");
                    emailText.setErrorEnabled(true);
                } else {
                  emailText.setErrorEnabled(false);
                }
            }

            @Override
            public void afterTextChanged(Editable s) {

            }
        });
      /*  editText.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                if(!TextUtils.isEmpty(e)) {
                    Snackbar.make(v, e, Snackbar.LENGTH_SHORT).show();
                    emailText.setErrorEnabled(false);
                } else {
                    emailText.setError("Input required");
                    emailText.setErrorEnabled(true);
                }
            }
        }); */
        next.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                if(check==false) {
                    Toast.makeText(getApplicationContext(), "Please make sure the details are right", Toast.LENGTH_LONG).show();

                } else{
                    Intent intent = new Intent(Personal.this, HomeDetails.class);
                    startActivity(intent);
                }


            }
        });
    }
    public static boolean checkEmail(String email) {

        Pattern EMAIL_ADDRESS_PATTERN = Pattern
                .compile("[a-zA-Z0-9+._%-+]{1,256}" + "@"
                        + "[a-zA-Z0-9][a-zA-Z0-9-]{0,64}" + "(" + "."
                        + "[a-zA-Z0-9][a-zA-Z0-9-]{0,25}" + ")+");
        return EMAIL_ADDRESS_PATTERN.matcher(email).matches();
    }
}

Answer 1

这应该有效，

android.util.Patterns.EMAIL_ADDRESS.matcher(emailText.getText().toString()).matches())

Answer 2

试试这个功能......

 public boolean isValidEmailAddress(String email) {
    String ePattern = "^[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+@((\\[[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\.[0-9]{1,3}\\])|(([a-zA-Z\\-0-9]+\\.)+[a-zA-Z]{2,}))$";
    java.util.regex.Pattern p = java.util.regex.Pattern.compile(ePattern);
    java.util.regex.Matcher m = p.matcher(email);
    return m.matches();
}

Answer 3

代码无效，因为您正在检查TextChangedListener中的String e实例，该实例是在onCreate方法中指定的，这意味着您没有检查EditText中的更新文本。无论EditText发生什么变化，它总是检查String实例，因此总是返回true。

您需要做的是从EditText获取更新的文本并使用它来运行您的检查功能。你可以这样做

@Override
public void afterTextChanged(Editable s) {
    String updatedText = s.toString();
    // do your check on updatedText here
}

Answer 4

解决了：

  @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

                Pattern EMAIL_ADDRESS_PATTERN = Pattern
                        .compile("[a-zA-Z0-9+._%-+]{1,256}" + "@"
                                + "[a-zA-Z0-9][a-zA-Z0-9-]{0,64}" + "(" + "."
                                + "[a-zA-Z0-9][a-zA-Z0-9-]{0,25}" + ")+");
                if(!EMAIL_ADDRESS_PATTERN.matcher(s).matches())
                {
                    emailText.setError("valid email id is required");
                    emailText.setErrorEnabled(true);
                } else {
                  emailText.setErrorEnabled(false);
                }
            }

Answer 5

试试这个

private boolean validateEmail() {
        String email = inputEmail.getText().toString().trim();

        if (email.isEmpty() || !isValidEmail(email)) {
            inputLayoutEmail.setError(getString(R.string.err_msg_email));
            requestFocus(inputEmail);
            return false;
        } else {
            inputLayoutEmail.setErrorEnabled(false);
        }

        return true;
    }

验证电子邮件不适用于textInputLayout

5 个答案: