使用jquery每三个底部滚动后“查看更多”按钮

时间:2015-10-17 04:42:52

标签: javascript jquery ajax infinite-scroll jquery-scrollable

我已经尝试了很多但是在每三次向下滚动后无法自动添加显示更多按钮。

当我到达页面底部时,它向下滚动无限次。我必须在三次滚动后停止它并且想要在每三个滚动后添加“查看更多”按钮。

1 个答案:

答案 0 :(得分:0)

尝试这样的事情:



<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
<head>
<style>
body {
    width: 200px;
    height: 100px;
    overflow: scroll;
}
</style>
</head>
<body >

<p>Try the scrollbar in div.</p>

In my younger and more vulnerable years my father gave me some advice that I've been turning over in my mind ever since.
<br><br>
'Whenever you feel like criticizing anyone,' he told me, just remember that all the people in this world haven't had the advantages that you've had.'


<p>Try the scrollbar in div.</p>

In my younger and more vulnerable years my father gave me some advice that I've been turning over in my mind ever since.
<br><br>
'Whenever you feel like criticizing anyone,' he told me, just remember that all the people in this world haven't had the advantages that you've had.'



<p>Try the scrollbar in div.</p>

In my younger and more vulnerable years my father gave me some advice that I've been turning over in my mind ever since.
<br><br>
'Whenever you feel like criticizing anyone,' he told me, just remember that all the people in this world haven't had the advantages that you've had.'



<p>Try the scrollbar in div.</p>

In my younger and more vulnerable years my father gave me some advice that I've been turning over in my mind ever since.
<br><br>
'Whenever you feel like criticizing anyone,' he told me, just remember that all the people in this world haven't had the advantages that you've had.'

<p>Scrolled <span id="demo">0</span> times.</p>

<script>


var lastScrollTop = 0;
var x = 0;
$(window).scroll(function(event){
   var st = $(this).scrollTop();
   if (st > lastScrollTop){
	   document.getElementById("demo").innerHTML = x += 1;
	    if( x%3 == 0){
	    	var i=document.createElement('button');
	    	i.innerHTML="more";
	     document.getElementsByTagName('body')[0].appendChild(i);
	    }
   } 
   lastScrollTop = st;
});
</script>

</body>
</html>
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