Question

我有一个带有列表框的表单，该表单报告了MySql数据库中记录的一些id客户端。我选择了一个这个id客户端我点击一个名为selected-record的按钮，我从数据库中获取数据，这些数据显示在php表中。这可以。然后我点击第二个名为delete-record的按钮，目标是获取客户端的id - 变量$num_client - 并运行sql delete指令删除记录。到目前为止我无法解决2分问题。

为什么要按＆＃34; delete_record＆＃34;按钮显示的表格pressind selected_record会立即在表单上取消吗？
为什么当我按delete_record指令echo num_client;`给出一个空值？

if ( isset($_POST['selected_record'])){
        // visualiazzazione tabella

        echo "<table border='1'>
    <tr>
        <th>Id cliente</th>
        <th>Ragione Sociale</th>
        <th>address</th>
        <th>village</th>
        <th>Provincia</th>
        <th>Contatto</th>
        <th>Dipartimento</th>
    </tr>";

        echo "<tr>";
        echo "<td>" . $num_client. "</td>";
        echo "<td>" . $rag_soc. "</td>";
        echo "<td>" . $address. "</td>";
        echo "<td>" . $village. "</td>";
        echo "<td>" . $provincia. "</td>";
        echo "<td>" . $contact_client. "</td>";
        echo "<td>" . $dipart. "</td>";
        echo "</tr>";

    echo "</table>";
    $result=mysqli_query($con,"SELECT id_cliente , ragione_sociale FROM clienti");
}

if( isset($_POST['delete_record'])) { 

// Here If I make echo $num_client this gives no value ??
//$sql_del = "DELETE FROM `db_ordini_clienti`.`clienti` WHERE `id_cliente` = $num_client";

}

为什么按一个按钮的PHP形式表显示消失？

0 个答案: