Question

我有一张表格，我曾用它来输入配方中的选择成分。我使用jquery脚本来允许我克隆＆＃34; 表格，以便我可以输入多种成分。

class IngredientListTemplate(Form):
    """
    Template to add a new ingredient to a recipe
    The 2 input are prefilled with the data from the query_factory
    """
    category = QuerySelectField(query_factory=categorylist, get_label=u'category', allow_blank=False)
    ingredient = QuerySelectField(query_factory=ingredientlist, get_label=u'ingredient', allow_blank=False)

    def __init__(self, *args, **kwargs):
           kwargs['csrf_enabled'] = False
           super(IngredientListTemplate, self).__init__(*args, **kwargs)

class IngredientListForm(Form):
    """
    Display the template
    """
    ingredient_list = FieldList(FormField(IngredientListTemplate), min_entries=1)

然后我将选择的结果存储在Recipeingredients表中，该表包含3个字段（id，recipe和许多成分）

class Recipeingredients(db.Model):
    """
    #Not sure how to store my list of ingredient
    #I need to obviously store the ingredient_id from Ingredientlist.
    #That might be enough since from the ingredient_id I know the rest...

    """
    id = db.Column(db.Integer, primary_key=True)
    recipe = db.Column(db.String(60), index=False, unique=False)
    ingredient_id = db.relationship( 'Ingredientlist', backref='ingredientlist.id', secondary='taxonomy' )

    def __init__(self, recipe, ingredient_id):
        self.recipe = recipe
        self.ingredient_id = ingredient_id

taxonomy = db.Table(
            'taxonomy',
            db.Column( 'recipe_id', db.Integer, db.ForeignKey( 'recipeingredients.id' ) ),
            db.Column( 'ingredient_id', db.Integer, db.ForeignKey( 'ingredientlist.id' ) ),
                    )

该部分正在运行，然后我可以显示特定食谱的内容。

接下来我正在尝试编辑该配方。我不知道该怎么办。这是我做的： 1 /我查询Recipeingredient表 2 /我将它传递给表单，然后渲染模板

@mod.route('/ingredients_selection/<int:recipe_id>', methods=['GET', 'POST'])
def ingredient_selection(recipe_id):

    recipe = Recipeingredients.query.get(recipe_id)
    #print recipe.ingredient_id #returns [5, 6, 9, 10, 19, 21, 23]
    form = IngredientListForm(obj=recipe)
    print form.data # returns {'ingredient_list': [{'category': None, 'ingredient': None}]}

我可以看到问题是因为Recipeingredient的查询与表单的预期不符，但我看不出如何使其匹配。

我是否想从查询中重新创建数据，以使其与表单所期望的相匹配？还是有更好的方法来实现它？

填充并编辑包含多对多查询的表单

0 个答案: