Question

我需要一些批处理脚本的帮助。我使用7zip命令行将每个rar文件（jpg文件）的输出发送到文本文件＆＃34; contents.txt＆＃34;

set PATH=%PATH%;"C:\Program Files\7-Zip"

echo. > contents.txt
for /R %%f in ("*.*") do (
7z l -r "%%f" | FIND /V "ing " | FIND /V "Igor Pavlov" | FIND /V "--" | FIND /V "Path" | FIND /V "Type" | FIND /V "Solid" | FIND /V "Blocks" | FIND /V "Multivolume" | FIND /V "Volumes" | FIND /V "Date" | FIND /V "---" | FIND /V "Physical Size" | FINDSTR /R /E ".jpg" >> contents.txt
)
PAUSE

contents.txt的输出是：

2001-07-17 08:39:00 ....A       326196       326164  A01.jpg
2001-07-17 08:39:00 ....A       338338       338338  A02.jpg
2001-07-17 08:39:00 ....A       332076       332076  A03.jpg
2001-07-17 08:39:00 ....A       458422       458422  A04.jpg
2001-07-17 08:39:00 ....A       376821       376821  A05.jpg
2001-07-17 08:39:00 ....A       326196       326164  B01.jpg
2001-07-17 08:39:00 ....A       338338       338338  B02.jpg
2001-07-17 08:39:00 ....A       332076       332076  B03.jpg
2001-07-17 08:39:00 ....A       458422       458422  B04.jpg
2001-07-17 08:39:00 ....A       376821       376821  B05.jpg
2001-07-17 08:39:00 ....A       326196       326164  C01.jpg
2001-07-17 08:39:00 ....A       338338       338338  C02.jpg
2001-07-17 08:39:00 ....A       332076       332076  C03.jpg
2001-07-17 08:39:00 ....A       458422       458422  C04.jpg
2001-07-17 08:39:00 ....A       376821       376821  C05.jpg

A * .jpg来自aa.rar，B * .jpg文件来自bb.rar，反之亦然。我试图读取contents.txt文件只获取第一个文件名。我将上面的脚本修改为：

for /R %%f in ("*.*") do (
7z l -r "%%f" | FIND /V "ing " | FIND /V "Igor Pavlov" | FIND /V "--" | FIND /V "Path" | FIND /V "Type" | FIND /V "Solid" | FIND /V "Blocks" | FIND /V "Multivolume" | FIND /V "Volumes" | FIND /V "Date" | FIND /V "---" | FIND /V "Physical Size" | FINDSTR /R /E ".jpg" >> contents.txt

for /f "usebackq delims=" %%i in (contents.txt) do (
set test="%%i"
echo %test%
)
)
PAUSE

但它不起作用。任何人都可以帮助我，我在这里做错了什么？ echo％test％输出＆＃34; test＆＃34;，而不是文本的内容。我是批处理脚本编程的新手，所以请原谅我的愚蠢。我想要以下输出：

aa.rar A01.jpg
bb.rar B01.jpg
cc.rar C01.jpg

Answer 1

原始命令7z ...生成输出

2001-07-17 08:39:00 ....A       326196       326164  A01.jpg

有趣的子串是＃6（A01.jpg）。您可以在for /f循环中处理输出并提取令牌＃6。然后为其添加文件名。

for /R %%A in ("*.*") do (
    rem  Loops through the output of the command  7z ...
    rem  and pass tokens (5th, remainder) as (%%B, %%C)
    for /f "tokens=5*" %%B in ('7z l -r "%%A" ^| FIND /V "ing " ^| FIND /V "Igor Pavlov" ^| FIND /V "--" ^| FIND /V "Path" ^| FIND /V "Type" ^| FIND /V "Solid" ^| FIND /V "Blocks" ^| FIND /V "Multivolume" ^| FIND /V "Volumes" ^| FIND /V "Date" ^| FIND /V "---" ^| FIND /V "Physical Size" ^| FINDSTR /R /E ".jpg"') do (
        echo %%A %%C>>contents.txt
    )        
)

batchscript：读取文件的内容

1 个答案: