Question

我不知道为什么上次我这样做时出现这个错误是因为我没有发起pygame，但我这次做了所以我真的不知道错误是什么

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import pygame


pygame.init()

pygame.display.set_caption("test")


screen = pygame.display.set_mode((800,600))

x = 0
y = 0
black = (0,0,0)
white = (255,255,255)
red = (200,0,0)
green = (0,200,0)
blue = (0,0,255)
bright_red = (255,0,0)
bright_green = (0,255,0)
gray = (153,153,153)

Player = pygame.image.load("player.png")


clock = pygame.time.Clock()

class player:

    def __init__(self ,x, y):

        self.x = x
        self.y = y
        self.width = 32
        self.height = 32


    def render(self,screen):
        screen.blit(Player)






def gameloop():
    gameExit = False
    while not gameExit:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()



screen.fill(white)







player.render(screen)
pygame.display.update()
clock.tick(60)


gameloop()
pygame.quit()
quit()

Answer 1

你打电话

player.render(screen(100,100))

但screen是Surface。 render类的player函数只有一个参数，所以你可能想调用

player.render(screen)

但是，只有player是player类的实例时，这才有效。您应该遵循命名约定并命名类Player以避免混淆和错误，然后使用

创建此类的实例

# create instance
player = Player(100, 100)

...other stuff...

# call render
player.render(screen)

'pygame.Surface'对象不可调用错误

1 个答案: