标题可能会产生误导,因为我似乎无法找到它的权利。但是它就在这里。
我有三张桌子。
Students
student_id | name
1 Rhon
Subjects
subject_id | subject_name | student_id
1 Physics 1
2 Math 1
Grades
grade_id | student_id | subject_id | grade
1 1 1 90
2 1 2 89
3 1 2 88
我想结果如下:
student_id | student_name | subject_name | grades
1 Rhon Physics 90
1 Rhon Math 88,89
我目前的查询是:
SELECT students.student_id, subjects.subject_id, string_agg(grades.grade, ',')
FROM students
JOIN subjects ON students.student_id = subjects.student_id
JOIN grades ON subjects.subject_id = grades.subject_id;
我的查询有问题吗?我错过了什么吗?错误说student_id
需要在GROUP BY子句中,但我不想这样做。谢谢你提前。
答案 0 :(得分:2)
您可以使用子查询执行此操作:
SELECT s.student_id, s.student_name, j.subject_name, g.grades
FROM students s
JOIN subjects j
JOIN (
SELECT student_id, subject_id, string_agg(grade, ',') AS grades
FROM grades
GROUP BY student_id, subject_id) g USING (student_id, subject_id);
为什么你不想GROUP BY student_id
?