Question

如果我有这样的查询

SELECT part, meta(loc).id FROM `bucket` as loc

结果如下：

[{
   "id": "loc_006b9cfc1ef849f68b694e35c99c4dfe",
   "part": {
            "name": "foo",
            "partNumber": "1806-0085S"
           },
 } ...

但如果我想要这样的东西怎么办：

SELECT part, { meta(loc).id } FROM `bucket` as loc  // won't work of course

我希望结果如下：

[{
   // see, this guy wrapped in its own object
   { "id": "loc_006b9cfc1ef849f68b694e35c99c4dfe" },  
   "part": {
            "name": "foo",
            "partNumber": "1806-0085S"
           },
 } ...

Answer 1

您可以使用：

SELECT part, { "id": meta(loc).id } AS some_alias
FROM `bucket` as loc

如何投影到对象中

1 个答案: