Question

这是我们当前的查询：

SELECT info.yearID, info.nameFirst, info.nameLast, info.HR
FROM (
SELECT a.yearID, a.nameFirst, a.nameLast, a.HR FROM (
SELECT @curRank := @curRank+1 as rank, i.nameFirst, i.nameLast, i.masterID, i.HR, i.yearID 
FROM (  SELECT (select @curRank := 0), m.nameFirst, b.yearID, m.nameLast, b.masterId, sum(b.HR) as HR
FROM master as m left join batting as b on b.masterID = m.masterID
WHERE b.yearID = 1882 group by b.masterID) 
as i ORDER BY i.HR desc
)a 
WHERE a.HR = (SELECT i.HR
FROM ( 
SELECT (select @curRank := 0), m.nameFirst, b.yearID, m.nameLast, b.masterId, sum(b.HR) as HR
FROM master as m left join batting as b on b.masterID = m.masterID
WHERE b.yearID = 1882 
group by b.masterID
) 
as i  ORDER BY i.HR desc limit 1)) as info ;

我们需要做到这一点，以便1882年不是硬编码，而是从1871年到2013年。

我不是在寻找答案，只是朝着正确的方向前进。

Answer 1

b.yearID = @yearVar

^^将解析@符号以及您对@curRank的处理方式将类似。它是提供某种动态价值的一种手段。

Answer 2

只需将其更改为：

WHERE b.yearID BETWEEN 1871 AND 2013

Mysql传递变量

2 个答案: