Question

我的程序，用于生成可接受的密码，除了输入提示之外不显示任何输出，它允许我输入密码但程序立即结束。我的调试器上没有错误或警告。想知道是否有人可以给我一些意见。

#include "stdafx.h"
#include <stdio.h>
#include <ctype.h>
#include <string.h>


int main()
{
    char password[15] = {'\0'};
    char search[15] = { '\0' };
    int a, b, c, d, e;
    char punct[] = { '!','@','#','$','%','^','&','*','?','_', '\0' };

    printf("Enter your test password: \n");
    fgets(password, 15, stdin );

    a = strnlen(password, 15);//judges length of search between the numbers 2 and 15
    b = strncmp(password, punct, 10);
    c = isalpha(strnlen(password,15));
    d = isdigit(strnlen(password, 15));
    e = a + b + c + d;

    if (a < 2 || a>15) {

        printf("Must have exactly 2-15 characters.\n");

        if (strncmp(password, punct, 10) == false) {//must have one of the characters included in password
            printf("Must have character punctutation\n");
        }
        if (isdigit(strnlen(password, 15)) == false) {
            printf("Must consist of at least one number 0-9.\n");
        }
        if (isalpha(strnlen(password, 15)) == false) {
            printf("Must consist of at least one letter a-z\n");
        }
        else {
            printf("You have inputted a legal password!\n");
        }

    }
        return 0;
    }

Answer 1

由于strnlen(password, 15)介于2和15之间，您未获得输出，请使用else部分：

if (a < 2 || a > 15) {
   ...
} else {
   /* your output here */
}

另一方面：

if (isdigit(strnlen(password, 15)) == false) {

是一个废话，isdigit检查字符是否为十进制数字，但是您传递size_t而不是char，isalpha相同。

命令提示符中没有输出

1 个答案: