Question

我有一个Json数组

{
  "cms18.test.silverbee.nl": {
    "domain": "cms18",
    "template": "default"
  },
  "dmmd.test.silverbee.nl": {
    "domain": "dmmd",
    "template": "default"
  },
  "opmaat.test.silverbee.nl": {
    "domain": "opmaat",
    "template": "opmaat"
  },
  "opmaatdebiteurenadvies.nl": {
    "domain": "opmaat",
    "template": "opmaat"
  },
  "navbar.test.silverbee.nl": {
    "domain": "navbar",
    "template": "default"
  },
  "test18.test.silverbee.nl": {
    "domain": "test18testsilverbeenl",
    "template": "test"
  },
  "huisartsplus.test.silverbee.nl": {
    "domain": "huisartsplustestsilverbeenl",
    "template": "huisartsplus"
  },
  "robertenrademaker.test.silverbee.nl": {
    "domain": "robertenrademakertestsilverbeenl",
    "template": "robert-en-rademaker"
  },
  "tilburg.test.silverbee.nl": {
    "domain": "tilburgtestsilverbeenl",
    "template": "default"
  },
  "cbk-groningen.test.silverbee.nl": {
    "domain": "cbk_groningentestsilverbeenl",
    "template": "cbk-groningen"
  },
  "getbusyinc.test.silverbee.nl": {
    "domain": "getbusyinctestsilverbeenl",
    "template": "getbusyinc"
  }
}

我得到了一个Php脚本，它获取输入值从上面将一个新元素推送到Json数组我不知道这是不是oke但是当我尝试推送它时我得到一个带有输入值的0它

 <?php 
    $url = $_POST['new_url'];
    $t_d = $_POST['t_d'];
    $t_t = $_POST['t_t'];
    $str = $url.":{"."domain:".$t_d.","."template:".$t_t."},";
          if (isset($url)) 
          {
            array_push($list, $str);
          }
    ?>

Answer 1

如果它真的是一个json数组，你应该尝试将字符串解码为数组：

<?php 
$decoded_list = json_decode($list, true); 
?>

然后将新元素推入数组？最后你可以做到

<?php 
$list = json_encode($decoded_list); 
?>

Answer 2

$str = $url.":{"."domain:".$t_d.","."template:".$t_t."},";
$str = json_decode($str);

          if (isset($url)) 
          {
            array_push($list, $str);
          }

Answer 3

首先，解码你的json：

$list = json_decode($list, true);

然后，根据您的用户输入值创建一个数组（下面的基本示例）：

$url = "google.com";
$t_d = "google";
$t_t = "googletwo";

$data[] = $url;
$data[] = array('domain' => $t_d, 'template' => $t_t);

附加数据：

if(isset($url)){
    array_push($temp, $data);
}

最后，将其编码回json，如下所示：

$json = json_encode($data);

输出：

[
  "google.com",
  {
    "domain": "google",
    "template": "googletwo"
  }
]

将新元素添加到Json数组

3 个答案: