Question

我正在尝试做一个登录类，检查所有字段是否正确，如果是，那么就是proccess。

我的代码：（login.php）

<?php
require('sql.php');

class login {

    private $user;
    private $email;
    private $doc;
    private $password;

    function login($field, $pass){
        $user = $field;
        $email = $field;
        $doc = strtoupper($field);
        $password = $pass;

        $this->getUser($user, $password, $r) ? $r : $this->getEmail($email, $password, $r) ? $r : $this->getDoc($doc, $password, $r) ? $r : null;
    }

    private function getUser($u, $p, &$r){
        global $sql;
        $count = 0;
        $check = $sql->query("SELECT ... ");
        while($row = $check->fetch_object()){
            $count++;
            $r = $row;
        }

        $count == 1 ? true : false;
    }

    private function getEmail($e, $p, &$r){ same as getUser()... }

    private function getDoc($d, $p, &$r){ same as getUser()... }
}

?>

现在在Index（index.php）

<html>

ALL HTML STUFF WITH THE FORM

</html>

<?php

require('login.php');

if(isset($_POST['submit'])){
    $login = new login(trim($sql->real_escape_string($_POST['user'])), md5(trim($sql->real_escape_string($_POST['pass']))));
    if($login != null){
        echo "SUCCESSFUL: ".$login->user;
    }else{
        echo "INCORRECT PASSWORD";
    }
}

?>

我们的想法是获得$login之类的值$login->user。但是告诉我一个错误...... 我怎样才能做到这一点？我的错误在哪里？

Answer 1

这会因私人$ user而导致错误;

公开$ user;因为私人会员不允许从外面访问

或者您可以执行以下操作

＆＃13;

public function getUsername(){
		return $this->username;
}

＆＃13;

并通过echo $ Obj-＆gt; getusername（）;

访问它

Answer 2

我不是说所有这些都有效。只是想知道我的意思。

您想要的是获取用户信息。为此，您创建了一个班级login。

为什么不创建一个User类来检索和存储信息。

如果构造函数出错。只需返回null。

class User {

    private $user;
    private $email;
    private $doc;
    private $password;

    private $detail1;
    private $detail2;
    private $detail3;
    private $detail4;    

    public function __constructfunction login($field, $pass){
        $user = $field;
        $email = $field;
        $doc = strtoupper($field);
        $password = $pass;

        $error = false;

        //Detail for User
        $count = 0;
        $check = $sql->query("SELECT ... WHERE username='.$this->user.' AND pass = '.$this->password.'");
        while($row = $check->fetch_object()){
            $count++;
            $r = $row;
        }

        if($count == 1)
        {
            $this->detail1 = $row['detail1'];
            $this->detail2 = $row['detail2'];
        }
        else
        {
            $error = true;
        }

        //Detail for Doc
        $count = 0;
        $check = $sql->query("SELECT ... WHERE username='.$this->user.' AND pass = '.$this->password.'");
        while($row = $check->fetch_object()){
            $count++;
            $r = $row;
        }

        if($count == 1)
        {
            $this->detail3 = $row['detail3'];
            $this->detail4 = $row['detail4'];
        }
        else
        {
            $error = true;
        }

        if(true === $error)
            return null;
    }

    public function getUser(){
        return $this->user;
    }

    public function getEmail(){
        return $this->doc;
    }

    public function getDoc(){
        return $this->doc;
    }

    //Maybe not usefull
    public function getPassword(){
        return $this->password;
    }
}

Answer 3

好的，谢谢大家，但我解决了问题!!

在登录的构造函数中我放了一个值。

public function login($field, $pass, &$r)

然后在index.php

$login = new login(//user, //pass, $r);

echo "SUCCESSFUL: ".$r->user;

这返回SQL查询的值。这就是我想要的。

再次感谢。

从self class PHP返回fetch_object

3 个答案: