有什么方法可以在线程启动时将参数传递给QThread(.start)?
我在stackoverflow中找到了一个使用pyqt线程的例子,但是我想知道如何传递参数,以防我希望工作线程处理我传递给它的run()函数的数据。
我引用的帖子:Busy indication with PyQt progress bar
代码:
class MyCustomWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(MyCustomWidget, self).__init__(parent)
layout = QtGui.QVBoxLayout(self)
self.progressBar = QtGui.QProgressBar(self)
self.progressBar.setRange(0,100)
button = QtGui.QPushButton("Start", self)
layout.addWidget(self.progressBar)
layout.addWidget(button)
button.clicked.connect(self.onStart)
self.myLongTask = TaskThread()
self.myLongTask.notifyProgress.connect(self.onProgress)
def onStart(self):
self.myLongTask.start()
def onProgress(self, i):
self.progressBar.setValue(i)
class TaskThread(QtCore.QThread):
notifyProgress = QtCore.pyqtSignal(int)
def run(self):
for i in range(101):
self.notifyProgress.emit(i)
time.sleep(0.1)
我想在调用.start时传递变量,例如
self.myLongTask.start(myvar)
.
.
def run(self, myvar):
但当然,pyqt不允许这样做。
答案 0 :(得分:2)
您无法将参数传递给run
,但您可以将参数传递给它的构造函数如下:
class TaskThread(QtCore.QThread):
def __init__(self, myvar, parent=None):
QThread.__init__(self, parent)
self.notifyProgress = QtCore.pyqtSignal(int)
self.myvar = myvar
def run(self):
#use self.myvar in your run
for i in range(101):
self.notifyProgress.emit(i)
time.sleep(0.1)
并在MyCustomWidget
班级中:
class MyCustomWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(MyCustomWidget, self).__init__(parent)
layout = QtGui.QVBoxLayout(self)
self.progressBar = QtGui.QProgressBar(self)
self.progressBar.setRange(0,100)
button = QtGui.QPushButton("Start", self)
layout.addWidget(self.progressBar)
layout.addWidget(button)
button.clicked.connect(self.onStart)
##############################################################
#and pass your argumetn to it's constructor here
self.myLongTask = TaskThread(myvar=myargument)
##############################################################
self.myLongTask.notifyProgress.connect(self.onProgress)
def onStart(self):
self.myLongTask.start()
def onProgress(self, i):
self.progressBar.setValue(i)