Question

我知道这个问题已经重复，但我不能按照我的情况说明这些例子。我正在查询Quake 2服务器以获取个人项目

 foreach ($results as $data) {
         echo "<pre>";
         print_r($data['players']);
    }

获得的信息：

[0] => Array
    (
        [frags] => 7
        [ping] => 28
        [nick] => Player
        [gq_name] => Player
        [gq_score] => 7
        [gq_ping] => 28
    )

[1] => Array
    (
        [frags] => 27
        [ping] => 31
        [nick] => lE'Heineken.
        [gq_name] => lE'Heineken.
        [gq_score] => 27
        [gq_ping] => 31
    )

）

那么如何在简单的表格中移动此信息呢？

<table>
<tr>
    <th>Players</th>
    <th>Frags</th>
    <th>Ping</th>
</tr>
<tr>
    <td></td>
    <td></td>
    <td></td>
</tr>

我正在尝试做q2servers

之类的事情

感谢您的时间，对不起我的英语。此致

Answer 1

我真的不需要你，但如果我理解得很好，你需要的是：

items = $("a");

$(items).each(function(index, item){
    b = $(item).attr('href');
    c = b.replace("#", "");
    d = "http://www.domainname.com/index/" + c + "/get";
    //console.log(d); //just to check them out
    item.attr('href', d);
});

Answer 2

我认为你需要这个：

echo "
<table>
<tr>
    <th>Players</th>
    <th>Frags</th>
    <th>Ping</th>
</tr>";

foreach ($results as $data) {
    // print_r($data['players']);
    echo "
    <tr>
        <th>".$data['players']['nick']."</th>
        <th>".$data['players']['frags']."</th>
        <th>".$data['players']['ping']."</th>
    </tr>"
}

echo "</table>";

Answer 3

然后试试这个，

 <table>
    <tr>
        <th>Players</th>
        <th>Frags</th>
        <th>Ping</th>
    </tr>
    <?php foreach ($results as $data) {
     <?php foreach($data['players'] as $item){ ?>
        <tr>
           <td><?php echo $item['gq_name']; ?></td>
           <td><?php echo $item['gq_frags']; ?></td>
           <td><?php echo $item['ping']; ?></td>

        </tr>
   <?php } ?>
    <?php } ?>
    </table>

数组多维到html表

3 个答案: