Question

我希望通过已替换字符但仍保留原始值的字段对结果进行分组。

这就是我所拥有的，但我需要在不更改结果的情况下返回原始URL值。

select Count(ID) as TotalClicks, Replace(URL, '/', '') as DistinctURL
  from email_click_throughs
 where emailid = @ID
group by  Replace(URL, '/', '')
order by TotalClicks desc

Answer 1

这会给你所描述的内容，但它会对“替换（URL ...”多余的分组进行分组，所以我可能会误解：

select Count(ID) as TotalClicks, URL as DistinctURL
from email_click_throughs
where emailid = @ID
group by Replace(URL, '/', ''), URL
order by TotalClicks desc

如果你只是想在取消'/'之后取回一个URL，即使两个是等效的，你也可以这样做

select Count(ID) as TotalClicks, Max(URL) as DistinctURL 
from email_click_throughs 
where emailid = @ID group by Replace(URL, '/', '') 
order by TotalClicks desc

但是你无法控制哪些“匹配”被删除。

在SQL中替换和分组

1 个答案: