Question

无论我尝试什么，我都会收到此响应错误。该方法似乎适用于ManyToOne Relationships但在OneToOne中失败。如果有人遇到并解决了这个问题，请提供帮助：

400 BAD REQUEST
{"error": "The 'order' field has no data and doesn't allow a default or null value."}

调试试用

尝试在“投放详细信息”中添加单独的主键“id”，因为我怀疑tastypie可能会失败，因为在创建相关字段之前无法生成订单ID。
删除了DeliveryDetails api中的订单字段，并尝试仅在订单资源中引用相关字段。

请求：

curl -X "POST" "http://localhost:5000/core/api/v1/order/" \
    -H "Content-Type: application/json" \
    -d "{\"source\":\"W\",\"delivery_detail\":{\"email\":\"valery.flemister@yam.com\"}}"

型号：

class Order(models.Model):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    created_at = models.DateTimeField(
        verbose_name='created at',
        auto_now_add=True
    )
    updated_at = models.DateTimeField(
        verbose_name='updated at',
        auto_now=True
    )
    SOURCE_TYPES = (
        ('I', 'iOS'),
        ('A', 'Android'),
        ('W', 'Web'),
        ('N', 'Not Applicable')
    )
    source = models.CharField(
        verbose_name='order source',
        max_length=1,
        choices=SOURCE_TYPES,
        default='N'
    )
class DeliveryDetail(models.Model):
    order = models.OneToOneField(
        to=Order,
        primary_key=True
    )
    email = models.EmailField(
        verbose_name='email address',
        max_length=255,
        blank=True,
        null=True
    )

API：

class OrderResource(ModelResource):
    delivery_detail = fields.ToOneField(
        to='core.api.v1_order.DeliveryDetailResource',
        attribute='deliverydetail',
        related_name='order',
        help_text='Delivery details',
        full=True
    )

    class Meta:
        queryset = Order.objects.all()
        resource_name = 'order'
class DeliveryDetailResource(ModelResource):
    order = fields.ToOneField(
        to=OrderResource,
        attribute='order'
    )

    class Meta:
        queryset = DeliveryDetail.objects.all()
        resource_name = 'delivery_detail'

Answer 1

OneToOne字段不允许空值。所以当时，您想要创建交货，订单尚未创建，因此订单为空。先将订单请求拆分，然后再转发，或设置ToOneField属性null=True

Django Tastypie - OneToOne关系POST不起作用

1 个答案: