Question

我正在编写一个计算平均成绩的C程序，并告诉您是否通过。用户可以根据需要选择尽可能多的尝试，并且将给出所有尝试的最终平均值。这是我的代码：

#include <stdio.h>

int main(void)
{
    int num1;
    double num2, num3, average, average_1;

    printf("Enter number of attempts: ");
    scanf("%d", &num1);

    while (num1 > 0) {
        printf("Enter your mark for subject one: ");
        scanf("%lf", &num2);

        printf("Enter your mark for subject two: ");
        scanf("%lf", &num3);

        if (num2 < 50 || num3 < 50) {
            printf("You have failed \n");
        } else {
            printf("You have passed \n");
        }

        num1--;
    }

    average = num1 * num2 * num3;
    average_1 = average / 100;

    printf("Average for all %d attempts is %.2f \n", num1, average_1);
}

这段代码的问题在于最后的输出，即最后的printf行，给出了0次尝试，0次为平均值。这是确切的输出：

Enter number of attempts: 2
Enter your mark for subject one: 49
Enter your mark for subject two: 96
You have failed
Enter your mark for subject one: 22
Enter your mark for subject two: 100
You have failed
Average for all 0 attempts is 0.00

Answer 1

您的循环将迭代，直到num1大于0。当它递减并成为0程序时，num1具有值0。因此，在这些表达式num1中0 -

average = num1*num2*num3;    // 0*num2*num3 therefore , 0
average_1 = average / 100;    // as average is 0 , thus result is 0

计算average_1的公式也是错误的。它应该是 -

average_1=average/3;    // you calculate average of 3 numbers

要获得正确的输出，请创建一个临时变量 -

int i=num1;
while(i>0){
 // your code 
 i--;
}

这样num1保持不变。

Answer 2

您已将平均计算部分放在错误的位置。一旦您离开while循环，num1将具有值0，因此所有相关计算都将返回0.

Answer 3

您正在减少num1，直到它变为0

while (num1 > 0) {
    // other code
    num1--;
}

然后自然

 average = num1*num2*num3;

成为

average = 0*num2*num3;

那是0

Answer 4

首先，因为你将num1减去一，直到0。

你应该使用for循环：

for(int counter = num1; num1 > 0; num--)

{ Your code here }

Answer 5

您正在改变变量num1。因此，当您完成循环时，您将获得num1 = 0。

我建议你做一个'for'而不是'while'。像这样：

#include <stdio.h>

int main(void) {

int num1, i;
double num2,num3,average,average_1;

printf("Enter number of attempts: ");
scanf("%d", &num1);

for(i = num1; i > 0; i--) {

        printf("Enter your mark for subject one: ");
        scanf("%lf", &num2);

        printf("Enter your mark for subject two: ");
        scanf("%lf", &num3);

        if (num2 < 50 || num3 < 50) {

                printf("You have failed \n");
        }
        else {
                printf("You have passed \n");
        }
}

average = num1*num2*num3;
average_1 = average / 100;
printf("Average for all %d attempts is %.2f \n", num1, average_1);
}

Answer 6

在while循环之后，你的num1将为0。

C程序输出错误？

6 个答案: