Question

使用cv::CommandLineParser时，是否可以解析任意长的非标志参数列表？
例如：

> app -a -b=2 a.txt b.txt c.txt ...

我希望能够访问所有非标记＆＃34;位置＆＃34; args，无需在keys规范中定义预定义数量的args。此号码仅由应用程序的呼叫者确定。

Answer 1

OpenCV CommandLineParser无法处理可变数量的位置参数。你可以：

传递额外的参数（例如-N），指定位置参数的数量;
将每个不以-开头的参数视为位置参数。

然后，您可以使用与cv::CommandLineParser相同的接口创建一个自定义命令行解析器，以处理可变数量的位置参数。

选项1

struct CustomCLP
{
    CustomCLP(int argc, const char* const argv[], const cv::String& keys, const String& positional_id)
    {
        String pos_key = "{" + positional_id + "|0|}";
        cv::CommandLineParser pos_clp(argc, argv, pos_key);
        _N = pos_clp.get<int>(positional_id);

        cv::String pos_keys = keys;
        for (int i=0; i<_N; ++i)
        {
            pos_keys += "{@pos" + to_string(i) + "||}";
        }

        _clp = new CommandLineParser(argc, argv, pos_keys);
    }

    ~CustomCLP()
    {
        delete _clp;
    }

    bool check() const {return _clp->check();}
    bool has(const cv::String& name) const {return _clp->has(name);}

    template<typename T>
    T get(const String& name, bool space_delete = true) const
    {
        return _clp->get<T>(name, space_delete);
    }
    template<typename T>
    T get(int index, bool space_delete = true) const
    {
        return _clp->get<T>(index, space_delete);
    }

    int n_positional_args() const { return _N;}

private:
    CommandLineParser* _clp;
    int _N;
};

您可以指定指定位置参数数量的额外参数（例如-N）。在构造函数中，您解析此数字，并为每个位置参数创建键。然后你可以一如既往地使用它。

选项2

// SO: http://stackoverflow.com/a/17976541/5008845
inline std::string trim(const std::string &s)
{
    auto  wsfront = std::find_if_not(s.begin(), s.end(), std::isspace);
    return std::string(wsfront, std::find_if_not(s.rbegin(), std::string::const_reverse_iterator(wsfront), std::isspace).base());
}

struct CustomCLP2
{
    CommandLineParser _clp;
    vector<std::string> pos_args;

public:
    CustomCLP2(int argc, const char* const argv[], const cv::String& keys) :
        _clp(argc, argv, keys)
    {
        for (int i = 1; i < argc; ++i)
        {
            std::string s(argv[i]);
            s = trim(s);
            if (s[0] == '-') continue;

            pos_args.push_back(s);
        }
    }

    bool check() const { return _clp.check(); }
    bool has(const cv::String& name) const { return _clp.has(name); }

    template<typename T>
    T get(const String& name, bool space_delete = true) const
    {
        return _clp.get<T>(name, space_delete);
    }

    template<typename T>
    T get(int index, bool space_delete = true) const
    {
        stringstream ss;
        ss << pos_args[index];
        T t;
        ss >> t;
        return t;
    }

    template<>
    cv::String get(int index, bool space_delete) const
    {
        return cv::String(pos_args[index]);
    }

    int n_positional_args() const { return pos_args.size(); }
};

在构造函数中，保存每个不以-开头的参数。然后你可以照常检索它。

<强>用法

请注意，该界面与CommandLineParser一致（在此示例中，about，getPathToApplication等一些方法不可用，但很容易将它们添加到自定义类中。

命令行参数是：

Option 1: -a -b=2 -N=3 a.txt b.txt c.txt
Option 2: -a -b=2 a.txt b.txt c.txt

代码：

#include <opencv2\opencv.hpp>
#include <iostream>
using namespace std;
using namespace cv;


struct CustomCLP
{
    CustomCLP(int argc, const char* const argv[], const cv::String& keys, const String& positional_id)
    {
        String pos_key = "{" + positional_id + "|0|}";
        cv::CommandLineParser pos_clp(argc, argv, pos_key);
        _N = pos_clp.get<int>(positional_id);

        cv::String pos_keys = keys;
        for (int i=0; i<_N; ++i)
        {
            pos_keys += "{@pos" + to_string(i) + "||}";
        }

        _clp = new CommandLineParser(argc, argv, pos_keys);
    }

    ~CustomCLP()
    {
        delete _clp;
    }

    bool check() const {return _clp->check();}
    bool has(const cv::String& name) const {return _clp->has(name);}

    template<typename T>
    T get(const String& name, bool space_delete = true) const
    {
        return _clp->get<T>(name, space_delete);
    }
    template<typename T>
    T get(int index, bool space_delete = true) const
    {
        return _clp->get<T>(index, space_delete);
    }

    int n_positional_args() const { return _N;}

private:
    CommandLineParser* _clp;
    int _N;
};

// SO: http://stackoverflow.com/a/17976541/5008845
inline std::string trim(const std::string &s)
{
    auto  wsfront = std::find_if_not(s.begin(), s.end(), std::isspace);
    return std::string(wsfront, std::find_if_not(s.rbegin(), std::string::const_reverse_iterator(wsfront), std::isspace).base());
}

struct CustomCLP2
{
    CommandLineParser _clp;
    vector<std::string> pos_args;

public:
    CustomCLP2(int argc, const char* const argv[], const cv::String& keys) :
        _clp(argc, argv, keys)
    {
        for (int i = 1; i < argc; ++i)
        {
            std::string s(argv[i]);
            s = trim(s);
            if (s[0] == '-') continue;

            pos_args.push_back(s);
        }
    }

    bool check() const { return _clp.check(); }
    bool has(const cv::String& name) const { return _clp.has(name); }

    template<typename T>
    T get(const String& name, bool space_delete = true) const
    {
        return _clp.get<T>(name, space_delete);
    }

    template<typename T>
    T get(int index, bool space_delete = true) const
    {
        stringstream ss;
        ss << pos_args[index];
        T t;
        ss >> t;
        return t;
    }

    template<>
    cv::String get(int index, bool space_delete) const
    {
        return cv::String(pos_args[index]);
    }

    int n_positional_args() const { return pos_args.size(); }
};


int main(int argc, char* argv[])
{
    String keys =   
        "{a | | whatever a}"
        "{b | 1 | whatever b}";

    //CustomCLP clp(argc, argv, keys, "N");
    CustomCLP2 clp(argc, argv, keys);

    if (clp.has("a")) {
        cout << "Has <a>" << endl;
    }
    else {
        cout << "Doesn't have <a>";
    }

    int b = clp.get<int>("b");
    cout << "<b> : " << b << endl;

    int N = clp.n_positional_args();

    for (int i = 0; i < N; ++i)
    {
        cout << to_string(i) << ": " << clp.get<cv::String>(i) << endl;
    }

    return 0;
}

OpenCV CommandLineParser未指定参数

1 个答案: