应用规则

Question

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嗨，我正在尝试在select for email列上应用规则。有时登录ID将是用户的电子邮件地址，如何应用规则，如果电子邮件出现在登录ID中，则不返回电子邮件列的任何内容？任何帮助将不胜感激，谢谢。

Answer 1

CASE...WHEN应该这样做。基本上，你明确地处理这两种情况。

SELECT LTRIM(RTRIM(HOST0149.LOGINID)) AS LOGINID,
   CASE WHEN LTRIM(RTRIM(HOST0140.EMAIL)) = LTRIM(RTRIM(HOST0149.LOGINID)) THEN NULL ELSE LTRIM(RTRIM(HOST0140.EMAIL)) END AS EMAIL,
   LTRIM(RTRIM(HOST0149.USERKEY)) AS ROLE
FROM HOST0149 LEFT JOIN 
   HOST0140 ON HOST0149.PERSONKEY = HOST0140.PERSONKEY

Answer 2

我认为case表达式符合您的要求：

SELECT LOGINID,
       (CASE WHEN LOGINID <> EMAIL THEN EMAIL END) as EMAIL,
       ROLE
FROM (SELECT LTRIM(RTRIM(HOST0149.LOGINID)) AS LOGINID,
             LTRIM(RTRIM(HOST0140.EMAIL)) AS EMAIL,
             LTRIM(RTRIM(HOST0149.USERKEY)) AS ROLE
      FROM HOST0149 LEFT JOIN 
           HOST0140
           ON HOST0149.PERSONKEY = HOST0140.PERSONKEY
     ) hh

Answer 3

这将得到结果：

echo '<span style="color:#E02F2F;text-align:center;font-size:25px;padding-left:38%;">Username or Password is valid</span>';     
header('Location:http://example.com/templates/georamble/index.php'); // Redirecting To Other Page