Question

我有＆＃34;公司名称＆＃34;，＆＃34;联系人＆＃34;，＆＃34;电话号码＆＃34;在我的下拉菜单中。当我选择＆＃34;联系人＆＃34;和＆＃34;公司＆＃34;并在文本框中输入一些名称，然后按＆＃34;搜索＆＃34;按钮它应该显示包含该人名的记录。如果我们不在文本框中输入任何名称并选择＆＃34;联系人＆＃34;和＆＃34;公司＆＃34;并按＆＃34;搜索＆＃34;按钮它应该显示＆＃34;联系人＆＃34;的所有记录。如果我选择＆＃34;电话＆＃34;和＆＃34;公司＆＃34;并在文本框中输入一些数字，它应该显示该记录，否则如果我们不输入任何数字，那么它应该显示电话号码的所有记录。这是我的代码如下：

purchase.jsp

<form action="view.jsp" method="post">
<select name="complan">
<option value="">Make a selection</option>
<option value="Company Name">Company Name</option>
<option value="Contact Person">Contact Person</option>
<option value="Phone Number">Phone Number</option>
</select>
<select name="category">
<option value=""> Make a selection </option>
<option value="company">company</option>
<option value="institution">institution</option>
<option value="hospital">hospital</option>
<option value="Others">Others</option>
</select>
<input type="text" name="search"/>
<input type="submit" value="Submit"/>
</form>

view.jsp的

<form>
<% 
String search=request.getParameter("search");
session.setAttribute("sea",search);
String category=request.getParameter("category");
session.setAttribute("cat",category);
String complan = request.getParameter("complan");
session.setAttribute("com",complan);
%>
<select onchange="setAction(this.value)">
<option value=''> Make a selection </option>
<option value='sample.jsp'> PDF</option>
<option value='XLS_LEAD.jsp'> XLS </option>
<option value='DOC_LEAD.jsp'> DOC </option>
<option value='XLSX_LEAD.jsp'> XLSX </option>
</select>
<br/>

<input type="submit" value="Submit">
</form>

sample.jsp

<body>
<%
Connection conn = null;
String sear=(String)session.getAttribute("sea");
String cate=(String)session.getAttribute("cat");
String comp=(String)session.getAttribute("com");

System.out.println("1 is:"+sear);
System.out.println("2 is:"+cate);
System.out.println("3 is:"+comp);
try 
{
    Class.forName("com.mysql.jdbc.Driver");
    conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/marketing_database","root","root");
    String sql="select * from lead where Category='" + cate.replaceAll("\\'","''") + "'";
    if(sear!=null && sear.trim().length()>0)
    {
        sql+=" AND Company_Name like '" + sear.replaceAll("\\'","''") + "%'";
        }
    else if(sear!=null && sear.trim().length()>0)
    {
        sql+=" AND Contact_Person like '" + sear.replaceAll("\\'","''") + "%'";
    }
    else
    {
        sql+=" AND Phone like '" + sear.replaceAll("\\'","''") + "%'";
    }

    String jrxmlFile ="D:/dev/tools/jasper files/report10.jrxml";
    InputStream input = new FileInputStream(new File(jrxmlFile));
    JasperDesign jasperDesign = JRXmlLoader.load(input);

    System.out.println("Compiling Report Designs");
    JasperReport jasperReport = JasperCompileManager.compileReport(jasperDesign);

    System.out.println("Creating JasperPrint Object");
    HashMap<String,Object> map = new HashMap<String,Object>();
    map.put("sql",sql);
            byte[] bytes = JasperRunManager.runReportToPdf(jasperReport, map, conn);

            response.setContentType("application/pdf");
            response.setContentLength(bytes.length);
            ServletOutputStream outStream = response.getOutputStream();
            outStream.write(bytes, 0, bytes.length);
            outStream.flush();
            outStream.close();
}
catch(Exception e) 
{e.printStackTrace();} 

        %>
</body>

report10.jrxml

<parameter name="sql" class="java.lang.String"/>
    <queryString>
    <![CDATA[$P!{sql}]]>
</queryString>

Answer 1

你得到了奇怪的代码：

if(sear!=null && sear.trim().length()>0)
{
    sql+=" AND Company_Name like '" + sear.replaceAll("\\'","''") + "%'";
    }
else if(sear!=null && sear.trim().length()>0)
{
    sql+=" AND Contact_Person like '" + sear.replaceAll("\\'","''") + "%'";
}

如果是，那么它永远不会进入你的其他地方

if (true){//i go here}else if (true){//How can I arrive here if it was false, 
  hence the else says it needs to be false}

所以在创建你的sql时，你需要根据你需要的语句做你。

如果（我有人和人）我这样做......

如果（我有电话）我这样做ecc。

如果您仍有问题通过评论，请尝试改进您的代码...

由于您通过电子邮件发送了一些代码，我将提供其他解决方法

String sql="select * from lead where Category Like'" + cate.replaceAll("\\'","''") + "%'";


//We check that user has input something in the search box
if(sear!=null && sear.trim().length()>0)
{
   boolean isnumber = isNumber(sear); //isNumber(String text) is a metod that you need to create;
   //I have not really understand what excatly you like,
   //but it could be like this
   if (isnumber || complan.equals("Phone Number")){
     sql+=" AND Phone like '" + sear.replaceAll("\\'","''") + "%'";
   } else if (complan.equals("Contact Person")){
     sql+=" AND Contact_Person like '" + sear.replaceAll("\\'","''") + "%'";
   }else{
     sql+=" AND Company_Name like '" + sear.replaceAll("\\'","''") + "%'";
   }
}else{
  //we do nothing since we like to show all records 
}

在这种情况下

如果输入的是一个号码或选定的电话号码，则会在电话号码栏中搜索。

如果输入不是数字并使用联系人进行搜索，则会在该列上选择

否则搜索公司名称

我不太喜欢这个号码的部分，因为您在选项中有电话号码，请注意，您永远找不到名为1234的公司，因为我们会搜索电话号码...为什么不按用户指示搜索？，如果没有显示，请选择默认值...

如果您不想找到与输入匹配的所有内容，但只需要更改确切的匹配

like '" + sear.replaceAll("\\'","''") + "%'"

到

= '" + sear.replaceAll("\\'","''") + "'"

如何将从下拉菜单中选择的值传递给jasper报告并显示记录

1 个答案: