Question

我正在创建一个包含string sentence或paragraph的程序。我对使用std不太熟悉:: 我不是要求某人为我做这件事，我只是想看看是否有人可以告诉我一个这方面的例子。

当选择第4个选项（“Split Words”）时，应将单词放入数组或结构中，并且每个单词应显示loop。在此之后，应执行重复删除，程序必须确定重复的单词并消除它们。在此之后，应再次打印单词列表。

对此的任何帮助将不胜感激。谢谢

代码:(我需要案例帮助＆＃39; D＆＃39;）

#include <iostream>
#include <cmath>
#include <cstdlib>
#include <string>
#include <algorithm>
#include <cctype>

using namespace std;
int main()
{

    string s;
    char selection;
    string w;

    cout << "Enter a paragraph or a sentence : " ;

    getline(cin, s);

    int sizeOfString = s.length(); 

    //cout << "The paragraph has " << sizeOfString << " characters. " << endl; ***Dummy call to see if size works. 

    //cout << "You entered " << s << endl; *** Dummy function !!

    cout << "" << endl;

    cout << "                 Menu          " << endl;
    cout <<"        ------------------------" << endl;
    cout << "" << endl;
    cout << "A -- Convert paragraph to all caps " << endl;
    cout << "B -- Convert paragraph to all lowercase " << endl;
    cout << "C -- Delete whitespaces " << endl;
    cout << "D -- Split words & remove duplicates " << endl;
    cout << "E -- Search a certain word " << endl;
    cout << "" << endl;
    cout << "Please select one of the above: " ;
    cin >> selection;
    cout << "" << endl;
    switch (selection) //Switch statement
    {
        case 'a':
        case 'A': cout << "You chose to convert the paragraph to all uppercase" << endl;
                  cout << "" << endl;
                  for(int i=0; s[i]!='\0'; i++)
                    {
                        s[i]=toupper(s[i]);
                    }
                    cout << "This is it: " << s << endl;
                  break;
        case 'b':
        case 'B': cout << "You chose to convert the paragragh to all lowercase" << endl;
                  cout << "" << endl;
                  for (int i=0; s[i] !='\0'; i++)
                  {
                      s[i]=tolower(s[i]);
                  }
                    cout << "This is it: " << s << endl;
                    break;
        case 'c':
        case 'C': cout << "You chose to delete the whitespaces in the paragraph" << endl;
                  cout << "" << endl;
                  for(int i=0; i<s.length(); i++)
                    if(s[i] == ' ') s.erase(i,1);
                  cout <<"This is it: " << s << endl;
                  break;
        case 'd':
        case 'D': cout << "You chose to split the words & remove the duplicates in the paragraph" << endl;
                  cout << "" << endl;




        case 'e':
        case 'E': cout << "You chose to search for a certain word in the paragraph. " << endl;
                  cout << "" << endl;
                  cout << "Enter the word you want to search for: ";
                  cin >> w;

                  s.find(w);
                  if ( s.find( w ) != std::string::npos )
                  {
                      cout << w << " was found in the paragraph. " << endl;

                  }
                 else 
                  {
                    cout << w << " was not found in the paragraph. " << endl;
                  }




    }


    return 0;
}

Answer 1

编写解析字符串 s 中的单词的代码（这里有一个方法：Split a string in C++?）。在解析它们时打印单词，然后将它们放在某种 set 容器中。设置容器不允许重复。完成解析单词后，迭代集并打印出单词（不会重复）。

如果您需要按照字符串中出现的顺序打印出去掉的单词，那么您可以在集合旁边保留向量。像以前一样，当您解析单词时，将它们添加到集合，但是从集合的 insert（）方法中检查返回的对（它可以告诉您是否插入的项目对于集合是新的，或者如果插入操作被拒绝，因为该集合已经包含一个等于您尝试插入的值的值：http://www.cplusplus.com/reference/set/set/insert/）。

std:vector<std:string> wordVector; // Assume populated with raw parsed words
std:set<std:string> deDupedSet;
std:vector<std:string> deDupedVector;

for (int i = 0; i < wordVector.size(); i++)
{
    if (deDupedSet.insert(wordVector[i]).second())
    {
        deDupedVector.push_back(wordVector[i]);
    {
}
// Print the deDupedVector afterwards

有人能告诉我一个例子吗？

1 个答案: