Question

首先，请知道我没有使用它作为真实世界的登录它纯粹是为了练习。我正在使用PHP / MySQLi，我试图实现准备好的语句，但我没有正确地做到这一点。这是我的工作代码，只有mysqli_escape_string：

$host="localhost";
$username="login";
$password="password";
$db_name="database";


$link=mysqli_connect("$host", "$username", "$password", "$db_name")or die("cannot connect to server"); 

$tbl_name=temp_members;

// Random confirmation code to be sent in email
$confirm_code=md5(uniqid(rand())); 

//from signup.php
$name=$_POST['name'];
$email=$_POST['email'];
$pwd=$_POST['password'];

$name = mysqli_real_escape_string($link, $name);
$email = mysqli_real_escape_string($link, $email);
$pwd = mysqli_real_escape_string($link, $pwd);

$pwd = password_hash($pwd, PASSWORD_DEFAULT);

// Insert data into temp_members
$sql="INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES('$confirm_code', '$name', '$email', '$pwd')";
$result=mysqli_query($link, $sql);


if($result){

    //email
    $to=$email;
    $subject="(no reply)";
    $header="from: Ben Pappas <mrbenpappas@gmail.com>";

    // message 
    $message="Hello ".$name.", Thanks for signing up! \r\n";
    $message.="Click on this link to activate your account: \r\n";
    $message.="http://www.monger.us/verify/confirmation.php?       passkey=$confirm_code";

    // send email
    $sentmail = mail($to,$subject,$message,$header);
}

这是我对PDO /预备陈述的（差）尝试：

$host="localhost";
$username="login";
$password="password";
$db_name="database";


$link = new PDO("mysql:host=$host;dbname=$db_name",$username,$password) or die("cannot connect to server");

$tbl_name=temp_members;

// Random confirmation code to be sent in email
$confirm_code=md5(uniqid(rand())); 

//from signup.php
$name=$_POST['name'];
$email=$_POST['email'];
$pwd=$_POST['password'];

$name = mysqli_real_escape_string($link, $name);
$email = mysqli_real_escape_string($link, $email);
$pwd = mysqli_real_escape_string($link, $pwd);

$pwd = password_hash($pwd, PASSWORD_DEFAULT);

// Insert data into temp_members

$statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES('$confirm_code', '$name', '$email', '$pwd')";
$statement->execute(array(
    $confirm_code => 'confirm_code',
    $email => 'email',
    $name => 'name'
));
$result = ($link, $statement);


if($result){

//email
$to=$email;
$subject="(no reply)";
$header="from: Ben Pappas <mrbenpappas@gmail.com>";

// message
$message="Hello ".$name.", Thanks for signing up! \r\n";
$message.="Click on this link to activate your account: \r\n";
$message.="http://www.monger.us/verify/confirmation.php?    passkey=$confirm_code";

// send email
$sentmail = mail($to,$subject,$message,$header);
}

我在调用语句变量的行上收到一条错误消息，上面写着意外的“;”

请原谅任何明显的错误我是一个padawan

Answer 1

$statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name, 
   email, password)VALUES('$confirm_code', '$name', '$email', '$pwd')";

应为：

$statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name,
   email, password)VALUES(:confirm_code, :name, :email, :pwd)");
$statement->execute(array(
':confirm_code' => $confirm_code,
':email' => $email,
':name' => $name,
':pwd' => $pwd
));

此外，不需要mysqli_real_escape_string代码：bind负责为您转义数据。

Answer 2

            $value = $_POST['value'];
            $stmt = $mysqli->prepare("INSERT INTO XYZ (field) VALUES (?)");
            $stmt->bind_param('s', $value);  
            $stmt->execute();

声明应如下所示。

“s”表示字符串，“i”表示int

Answer 3

你是missing $ statement行上的close括号：

试试这个

$statement = $link->prepare("INSERT INTO $tbl_name(confirm_code, name, email, password)VALUES(:confirm_code, :name, :email, :pwd)");
$statement->execute(array(
    ':confirm_code' => $confirm_code,
    ':email' => $email,
    ':name'  => $name,
    ':pwd' => $pwd
));

准备好的声明+ PDO

3 个答案: