从ajax响应中设置Image src

时间:2015-10-13 18:36:53

标签: jquery ajax image base64

我想在我的页面中设置一个图像src,其中包含我从ajax调用响应中收到的图像,但是当我使用响应设置图像src时,我得到一个损坏的图像图标。

下面的

是ajax调用

buildscript {
    //repositories { jcenter() }
    dependencies {
        compile fileTree(dir: 'libs', include: '*.jar')
        classpath 'com.github.jengelman.gradle.plugins:shadow:1.2.2'
    }
}

错误

enter image description here

1 个答案:

答案 0 :(得分:1)

找到我的问题的解决方案

https://stackoverflow.com/a/25371174/3518278

必须添加mime-type

mimeType: "text/plain; charset=x-user-defined",

$("#img_carousel").attr('src', 'data:image/jpeg;base64,' + base64Encode(data));

function base64Encode(str) {
                var CHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
                var out = "", i = 0, len = str.length, c1, c2, c3;
                while (i < len) {
                    c1 = str.charCodeAt(i++) & 0xff;
                    if (i == len) {
                        out += CHARS.charAt(c1 >> 2);
                        out += CHARS.charAt((c1 & 0x3) << 4);
                        out += "==";
                        break;
                    }
                    c2 = str.charCodeAt(i++);
                    if (i == len) {
                        out += CHARS.charAt(c1 >> 2);
                        out += CHARS.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));
                        out += CHARS.charAt((c2 & 0xF) << 2);
                        out += "=";
                        break;
                    }
                    c3 = str.charCodeAt(i++);
                    out += CHARS.charAt(c1 >> 2);
                    out += CHARS.charAt(((c1 & 0x3) << 4) | ((c2 & 0xF0) >> 4));
                    out += CHARS.charAt(((c2 & 0xF) << 2) | ((c3 & 0xC0) >> 6));
                    out += CHARS.charAt(c3 & 0x3F);
                }
                return out;
            }