MySQL - 使用设置差异与操作数应包含1列

Question

我有以下MYSQL查询工作：

SELECT 
    a.author_name, COUNT(*)
FROM
    publication p,
    authored a
WHERE
    a.pubkey = p.pubkey
        AND p.pubkey LIKE '%/asd/%'
GROUP BY a.author_name
HAVING COUNT(*) >= 1;

上述查询是显示在一本书中至少发布一本包含“asd”字样的图书的作者的姓名。

我的想法就是设定差异。我试图通过使用以下sql语句找到没有发布包含“asd”一词的书的作者：

SELECT 
    a.author_name
FROM
    author a,publication p
WHERE
   a.pubkey = p.pubkey AND a.author_name NOT IN (SELECT 
            a1.author_name, COUNT(*)
        FROM
            publication p1,
            author a1
        WHERE
            a1.pubkey = p1.pubkey
                AND p1.pubkey LIKE '%/asd/%'
        GROUP BY a1.author_name
        HAVING COUNT(*) >= 1);

但由于某种原因，我不断收到此错误“操作数应包含1列，我无法找到错误。

谢谢。

Answer 1

尝试从内部查询中删除计数。这样的事可能......

SELECT 
    a.author_name
FROM
    author a,publication p
WHERE
   a.pubkey = p.pubkey AND a.author_name NOT IN (SELECT 
            a1.author_name
        FROM
            publication p1,
            author a1
        WHERE
            a1.pubkey = p1.pubkey
                AND p1.pubkey LIKE '%/asd/%'
        GROUP BY a1.author_name
        HAVING COUNT(*) >= 1);