Question

我们正在制作一个Gibberish转换器。用户输入一个选定的单词和两个乱码线（每两个字符长），它们将替换所选单词中的元音。

import string

print("English to Gibberish translator")

user = ""

vowels = "aeiouAEIOU"

while user.lower() != "n":


    cons1 = input("Enter your first Gibberish syllable (add * for the vowel substitute): ")
    check = True
    while check:
        for letter in cons1:
            if letter not in string.ascii_letters and letter != "*":
                cons1 = input("Syllable must only contain letters or a wildcard ('*'): ")
                break
        else:
            check = False

    cons2 = input("Enter the second Gibberish syllable (* for vowel substitute): ")
    while check:
        for letter in cons2:
            if letter not in string.ascii_letters and letter != "*":
                cons2 = input("Syllable must only contain letters or a wildcard ('*'): ")
                break
        else:
            check = False

如您所见，有两个检查循环检查用户是否估算了正确的行。我们必须使用def函数来替换此代码，而是将其调用两次。我怎么能这样做呢？

Answer 1

def inputgib(pro):
    val = input(pro)
    valid = string.ascii_letters + ["*"]
    return val if all(c in valid for c in val) else inputgib(pro)
cons1 = inputgib("Enter your first Gibberish syllable (add * for the vowel substitute): ")
cons2 = inputgib("Enter the second Gibberish syllable (* for vowel substitute): ")

这个递归函数将验证压缩到生成器表达式中，如果该行无效，则使用相同的提示再次调用自身。

需要使用def来调用两次检查功能

1 个答案: