Question

所以在此应用Drawing belongsTo Customer中。我有数据表

            <table id='drawing-table' class="table table-bordered table-hover">
                <thead>
                    <tr>
                        <th>Drawing number</th>
                        <th>Customer</th>
                    </tr>
                </thead>
            </table>

表示$darwing->number和$customer->title。要加载信息I use yajra\Datatables\Datatables;。

使用此JS方法加载数据：

$(function () {
    $('#drawing-table').DataTable({
        processing: true,
        serverSide: true,
        ajax: '{{route('drawings.datatable')}}',
        columns: [
            { data: 'number', name: 'number' },
            { data: 'customer.title', name: 'customer' },
        ]
    });
});

这个Laravel方法：

public function datatable()
{
    $drawings = Drawing::select(array('drawings.id','drawings.number'));

    return Datatables::of(Drawing::with('customer')->select('*'))->make(true);
}

问题

如何使数据表搜索窗口与$customer->title一起使用？
如何将图纸编号和客户标题显示为链接？

Answer 1

    public function datatable()
    {

        //reference customer table
        $drawings = DB::table('customers')
            // join it with drawing table
            ->join('drawings', 'drawings.customer_id', '=', 'customers.id')
            //select columns for new virtual table. ID columns must be renamed, because they have the same title
            ->select(['drawings.id AS drawing_id', 'drawings.number', 'customers.title', 'customers.id AS customer_id']);

        // feed new virtual table to datatables and let it preform rest of the query (like, limit, skip, order etc.)
        return Datatables::of($drawings)
            ->editColumn('title', function($drawings) {
                return '<a href="'.route('customers.show', $drawings->customer_id).'">' . $drawings->title . '</a>';
            })  
            ->editColumn('number', function($drawings) {
                return '<a href="'.route('drawings.show', $drawings->drawing_id).'">' . $drawings->number . '</a>';
            })  
            ->make(true);
    }

花了很多时间试图解决这个问题，希望能节省一些时间。 http://datatables.yajrabox.com/fluent/joins

Answer 2

我不确定你的第一个问题。数据表搜索窗口将搜索所有内容。你想让它专门针对1列吗？

要回答第二个问题，您可以编辑列输出。试试这个

$drawings = Drawing::select(array('drawings.id','drawings.number'));

return Datatables::of(Drawing::with('customer')->select('*'))
        ->editColumn('customer', function($drawings) {
            return '<a href="#">' . $drawings->customer . '</a>';
        })              
        ->make(true);

修改

要实现您想要的搜索，您需要执行以下操作：

public function datatable(Request $request) { $drawings = Drawing::select(array('drawings.id','drawings.number')); return Datatables::of(Drawing::with('customer')->select('*')) ->filter(function ($query) use ($request) { if ($request->has('name')) { $query->where('customer.customer_name', 'like', "%{$request->get('name')}%"); } }) ->editColumn('customer', function($drawings) { return '<a href="#">' . $drawings->customer->customer_name . '</a>'; }) ->make(true); }

然后，在你的JS中

$(function () { $('#drawing-table').DataTable({ processing: true, serverSide: true, ajax: { url: '{{route('drawings.datatable')}}', data: function (d) { d.name = $('input[name=name]').val(); } }, columns: [ { data: 'number', name: 'number' }, { data: 'customer.title', name: 'customer' }, ] }); });

这是未经测试的，但应该达到你想要的效果。

Answer 3

您还可以使用与yajra的优雅关系，这是示例代码。

$sub_sectors = Sector::where('parent_id', '>', 0)->with('parent')->latest()->get();
$sub_sectors->each(function($sub_sectors){
    $sub_sectors->sector = $sub_sectors->parent->title['en'];
});

在此示例中，您可以通过每种方法获取扇区名称来获得针对子扇区的扇区，现在您可以在yajra表中显示扇区

laravel数据关系

3 个答案: