Question

我有一个像这样的隐藏表格

HTML

<h2> First Date</h2>
<input type="hidden" class="datepicker" id="startDate" value="29-10-2015" />

<h2> Second Date</h2>
<input type="hidden" class="datepicker" id="endDate" value="29-12-2015" />

<button type="button" id="test">Click It</button>
<p>Total Weeks</p>

JAVASCRIPT

$("input").datepicker();

    $('#test').click(function () {
        var end = $('#endDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();
        var start = $('#startDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();

        var $weekDiff = Math.floor((end - start + 1) / (1000 * 60 * 60 * 24) / 7);

        alert('Total Weeks :'+$weekDiff);
    });

当我在数据库的隐藏输入字段中打印日期时，它采用我在此处粘贴的格式

JSFiddle

Answer 1

转换为ms并除以每周ms。

// date1 = $('#startDate').datepicker('getDate');
// date2 = $('#endDate').datepicker('getDate');

function nWeeks(date1, date2) {
    var WEEK = 1000 * 60 * 60 * 24 * 7;

    var date1ms = date1.getTime();
    var date2ms = date2.getTime();

    var diff = Math.abs(date2ms - date1ms);

    return Math.floor(diff / WEEK);
}

Here是关于JS日期对象的参考。

Answer 2

这是一种简单的方法：

＆＃13;

$("input").datepicker();
$('#test').click(function() {
  var end = $('#endDate').datepicker('getDate');
  var start = $('#startDate').datepicker('getDate');
  var $weekDiff = Math.floor((end - start + 1) / (1000 * 60 * 60 * 24) / 7);

  $('#total').html($weekDiff);
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.10.3/jquery-ui.min.js"></script>
<h2> First Date</h2>
<input type="text" class="datepicker" id="startDate" value="12/10/2015" />
<h2> Second Date</h2>
<input type="text" class="datepicker" id="endDate" value="12/29/2015" />
<button type="button" id="test">Click It</button>
<p>Total Weeks</p><span id="total"></span>

＆＃13;

FIDDLE

Answer 3

您正在尝试将JS字符串转换为数学表达式中的整数，这将导致NaN。

所以你需要先做Date.parse( string )。

随着你的小提琴，它将是：

$("input").datepicker();

$('#test').click(function () {
    var end = $('#endDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();
    var start = $('#startDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();

    end = Date.parse( end );
    start = Date.parse( start );

    alert( [end, start] );

    var $weekDiff = Math.floor((end - start + 1) / (1000 * 60 * 60 * 24) / 7);

    alert('Total Weeks :'+$weekDiff);
});

使用es6和一些缩短：

$("input").datepicker();

$('#test').click( () => {
    const [end, start] = ["#endDate", "startDate"]
        .map( e => Date.parse( e.datepicker({ dateFormat: 'dd-mm-yyyy'}).val() ) );

    const diff = Math.floor((end - start + 1) / (1000 * 60 * 60 * 24) / 7);
    console.log('Total Weeks :' + diff);
});

Answer 4

你可以尝试这样的事情。

$("input").datepicker();

$('#test').click(function () {
    var end = $('#endDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();
    var start = $('#startDate').datepicker({ dateFormat: 'dd-mm-yyyy'}).val();

    var $weekDiff = Math.floor((end - start + 1) / (1000 * 60 * 60 * 24) / 7);

    alert(daydiff(parseDate(start), parseDate(end)));
});



function parseDate(str) {
    var mdy = str.split('/')
    return new Date(mdy[2], mdy[0]-1, mdy[1]);
}

function daydiff(first, second) {
    return Math.round((second-first)/(1000*60*60*24) / 7);
}

更新了您的jsfiddle

Answer 5

它对我有用。

$('#test').click(function () {
    var end = $('#endDate').datepicker({dateFormat: 'dd-mm-yyyy'}).val();
    var start = $('#startDate').datepicker({dateFormat: 'dd-mm-yyyy'}).val();
    var aDate1 = end.split('-');
    var aDate2 = start.split('-');
    end = Date.UTC(aDate1[2], aDate1[1] - 1, aDate1[0]);
    start = Date.UTC(aDate2[2], aDate2[1] - 1, aDate2[0]);
    alert(Math.floor((end - start) / (1000 * 60 * 60 * 24)));
});

试着在Jquery

5 个答案: