Xcode7 ios9不支持armv7和armv7s架构设备

Question

以下是ios-charts库集成的构建设置。 我的应用目标和图表目标的构建设置如下。

但是当我在Xcode7中运行应用程序时，它会让我发出警告

xcode7以后是否已停止支持较旧的设备

注意：我正在使用iPhone5进行测试，运行ios 8.4.1

Answer 1

我之前也遇到过同样的问题。我的设备位于Xcode，Xcode 7版本为7（iOS 9）。我希望在设备连接时运行应用程序，但经过一天的搜索后，我发现iOS SDK 9包含SDK版本9（def partition(a, p, r, pivot): """ Permutes the elements of a[p..r] (inclusive) in-place: first elements <= a[r], then a[r], then those > a[r]. Returns the new location (index) of pivot value a[r] in the array. """ i = p - 1 for j in range(p, r + 1): if a[j] < pivot: i = i + 1 a[i], a[j] = a[j], a[i] return i def mom(a, left, right): """ Returns the median of medians for array a. """ length = right - left + 1 if length <= 0: return if length <= 5: return sorted(a[left : right + 1])[length/2] num_of_medians = length/5 medians = [mom(a, left + 5*i, left + 5 * (i + 1) - 1) for i in range(num_of_medians)] return mom(medians, 0, len(medians) - 1) def kth(a, left, right, k): """ ~~~~~ NOTE: k here means k-th smallest element. So in an array of length 10, the k-th smallest element is the (len(array) - k)-th largest element. ~~~~~ Partitions the array a around the median of medians pivot. Keeps finding new pivots until the pivot == k. Then the partition is around k. then a[(len(a) - k)...(len(a)-1)] will output the largest k elements (not sorted) """ pivotIndex = mom(a, left, right) pivotIndex = partition(a, left, right, pivotIndex) while k != pivotIndex + 1: if k > pivotIndex + 1: pivotIndex = kth(a, pivotIndex + 1, right, k) elif k < pivotIndex + 1: pivotIndex = kth(a, left, pivotIndex, k) return pivotIndex + 1 #this is index of the kth largest element ），它不允许在设备上连接或直接运行应用程序其os版本低于iOS 9。

要运行应用，我已将设备更新为iOS 9＆amp;它像魅力一样工作。！