Question

我正在尝试从JSON获取一些字段。问题是，如果只生成一个，那么我可以通过使用以下

轻松获得它

[{"sname":"Akshay","class":"MCA","latitude":"73.6562320000","longitude":"72.2041200000"}]

使用以下类

public class Example {

    @SerializedName("sname")
    @Expose
    private String sname;

    @SerializedName("class")
    @Expose
    private String _class;

    @SerializedName("latitude")
    @Expose
    private String latitude;

    @SerializedName("longitude")
    @Expose
    private String longitude;

    /**
    * 
    * @return
    * The sname
    */
    public String getSname() {
        return sname;
    }

    /**
    * 
    * @param sname
    * The sname
    */
    public void setSname(String sname) {
        this.sname = sname;
    }

    /**
    * 
    * @return
    * The _class
    */
    public String getClass_() {
        return _class;
    }

    /**
    * 
    * @param _class
    * The class
    */
    public void setClass_(String _class) {
        this._class = _class;
    }

    /**
    * 
    * @return
    * The latitude
    */
    public String getLatitude() {
        return latitude;
    }

    /**
    * 
    * @param latitude
    * The latitude
    */
    public void setLatitude(String latitude) {
        this.latitude = latitude;
    }

    /**
    * 
    * @return
    * The longitude
    */
    public String getLongitude() {
        return longitude;
    }

    /**
    * 
    * @param longitude
    * The longitude
    */
    public void setLongitude(String longitude) {
        this.longitude = longitude;
    }
}

但它可以生成数百条记录，我需要获取它们并存储在数组中我不知道怎么做.. 示例

[{"sname":"khfksjd","class":"djfhd","latitude":"73.6562320000","longitude":"72.2041200000"},{"sname":"ak","class":"hdhdh","latitude":"30.1394476766","longitude":"77.2564416164"}{"sname":"dffdf","class":"dfdfdff","latitude":"73.6562320000","longitude":"72.2041200000"},{"sname":"adfdfd","class":"hdxcxchdh","latitude":"30.1394476766","longitude":"77.2564416164"}]

任何人都可以帮助我吗？

Answer 1

只需让你的方法返回List＆lt; \ YourObjectHere＆gt;而不只是 YourObject

Answer 2

创建另一个POJO类，如下所示。

import java.util.ArrayList;

public class DataExample {

    private ArrayList<Example> arrayList = new ArrayList<Example>();

    public ArrayList<Example> getArrayList() {
        return arrayList;
    }

    public void setArrayList(ArrayList<Example> arrayList) {
        this.arrayList = arrayList;
    }
}

我假设你的界面是这样的：

        @FormUrlEncoded
        @POST("/getExampleData")
        DataExample requestExampleData( @Field("userId") String userId);

在您的活动中执行以下操作，

 class GetExampleData extends AsyncTask<Void, Void, Void> {

        @Override
        protected Void doInBackground(Void... params) {

            try {
                APIRequests request = Utils.getRestAdapter().create(
                        APIRequests.class);
                DataExample mResponseData = request.requestExampleData("userId");
                // Just for understanding purpose.
                //you can get your list by accessing the mResponseData.

                Yourlist = mResponseData.getArrayList();

                // Yourlist now have all the values you need.

            } catch (Exception ex) {

            }
            return null;
        }
    }

就是这样。你很高兴！

Android使用改造来获取所有字段

2 个答案: